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3 years ago

B-c,when b=8 and c=7

1 answer:

8 0

If I understand your question correctly then it's simple all you have to do is use the numbers in the place of the b and c so the question would be what is 8-7 which equals 1

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Which one should I choose?

amid [387]

Answer:

Step-by-step explanation:

3 0

3 years ago

Que is on pic.i can't able to type in text.

ad-work [718]

It's not difficult to compute the values of $A$ and $B$ directly:

$A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}$
$A=\tan^{-1}(\sin\theta)-\dfrac\pi4$

$B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt$
$B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}$
$B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2$

Let's assume $0$ , so that $|\csc\theta|=\csc\theta$ .

Now,

$\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}$
$\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}$
$\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)$
$\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)$

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in $A$ and $B$ .

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3 years ago

Which example would be likely to give a valid conclusion?

m_a_m_a [10]

Thirty students are randomly sampled about their hair color.

This is for two reasons,. Firstly, randomness is very important in drawing conclusions. Secondly, it is less of an opinion question and more fact based.

7 0

4 years ago

Read 2 more answers

Okay guys last one for now ill mark brainlest

andrezito [222]

Answer:

the answer is 3 cm

Step-by-step explanation:

8*5*3=120cm

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3 years ago

Write a two-step equation that involves multiplication and subtraction, includes a negative coefficient , and has a solution of

Allisa [31]

Answer:

-60x+20 = -400

x equals 7

Step-by-step explanation:

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3 years ago