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Books are always useful . Give me a "<em>thank</em><em> </em><em>you</em><em>"</em><em> </em>if i've been helpful
For the answer to the question above,
<span>Q = amount of heat (kJ) </span>
<span>cp = specific heat capacity (kJ/kg.K) = 4.187 kJ/kgK </span>
<span>m = mass (kg) </span>
<span>dT = temperature difference between hot and cold side (K). Note: dt in °C = dt in Kelvin </span>
<span>Q = 100kg * (4.187 kJ/kgK) * 15 K </span>
<span>Q = 6,280.5 KJ = 6,280,500 J = 1,501,075.5 cal</span>
Because the effective charge of the nucleus increase from left to eight due to the increasing number of protons.
The greater charge pulls the electrons closer to the nucleus, decreasing the radius.
The answer to this question is:
Simply it can be calculate using the equation Q=It, here Q is the charge in coulombs , I current in Amps and t is the time in seconds.
so the answer is Q = 10*60 = 600 coulomb.
