To solve this problem we will use the related concepts in Newtonian laws that describe the force of gravitational attraction. We will use the given value and then we will obtain the proportion of the new force depending on the Radius. From there we will observe how much the force of attraction increases in the new distance.
Planet gravitational force
Distance between planet and star
Gravitational force is
Applying the new distance,
Replacing with the previous force,
Replacing our values
Therefore the magnitude of the force on the star due to the planet is
Answer:
The horizontal distance of Sosa is 276.526 ft or 84.28 meter.
Explanation:
As shown in the figure, let point O is the starting point of Sosa. She travels 361 ft at an angle 50 degree with the horizontal.
sin 50 =
0.7660 = h / 361
h = 276.526 ft
h = 84.28 meter
The horizontal distance of Sosa is 276.526 ft or 84.28 meter.