"Maritime" air . . . . . always high relative humidity
"Polar" air . . . . . always cold
"Maritime polar" air . . . . . choice-A
Answer:
The final velocity is 31.86 m/s.
Explanation:
The final velocity can be found using the following equation:

Where:
is the final velocity =?
is the initial velocity = 33.9 m/s
a is the acceleration = -2.02 m/s²
t is the time = 1.01 s

Therefore, the final velocity is 31.86 m/s.
I hope it helps you!
Answer:
2
Explanation:
BRAINLIEST?? AND THANK ME LATER!!! HOPE THIS HELPED!!!
<h2>
Electric field at the location of the charge is 169.97 N/C</h2>
Explanation:
Electric field is the ratio of force and charge.
Force, F = 6 x 10⁻⁶ N
Charge, q = 3.53 x 10⁻⁸ C
We have

Electric field at the location of the charge is 169.97 N/C