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Ghella [55]
3 years ago
11

How much work is done lifting a 12-m chain that is initially coiled on the ground and has a density 2 kg/m so that its top end i

s 8 m above the ground? (Assume that acceleration due to gravity is g = 9.8 m/s2.)
Physics
1 answer:
Irina18 [472]3 years ago
8 0

Answer:

W = 627.2 J

Explanation:

Given:

\rho_{chain} = 2kg/m

length of chain = 12 m

length pulled will be = 8 m

We know

Work done (W) = mgh

where

m = mass of the object

g= acceleration due to gravity

h = displacement

For a small length dy of the chain, the work done can be written as:

dW  = (mass of the small length pulled)× g×dy

dW = 2kg/m ×dy×9.8×y

where, y is the distance from the ground level of the end of chain

integerating the above equation

W = \int\limits^8_0 {19.6y} \, dx

W =[19.6\frac{y^2}{2}]_{0}^{8}

W = 627.2 J

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Answer:  

a) the magnitude of r is  184.62

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Explanation:

Given the data in the question;

as illustrated in the image blow;

To find the the magnitude of r, we will use the Pythagoras theorem

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