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3 years ago

What is the equation of a line that passes through points (2,0) and (6,-4)

Mathematics

1 answer:

romanna [79]3 years ago

5 0

Answer:

y = -x + 2

Step-by-step explanation:

We are asked to find the equation of a line

Step 1: find the slope

We are given two points

( 2 , 0) ( 6 , -4)

m = (y_2 - y_1 )/ (x_2 - x_1)

x_1 = 2

y_1 = 0

x_2 = 6

y_2 = -4

Insert the values

m = ( -4 - 0) / ( 6 - 2)

m = -4 / 4

m = -1

Step 2 : substitute m into the equation

y = mx + c

y = -1x + c

Step 3: substitute any of the two points into the equation

Let's pick ( 6 , -4)

x = 6

y = -4

y = mx + c

y = -1x + c

-4 = -1(6) + c

-4 = -6 + c

c = -4 + 6

c = 2

Step 4: substitute c = 2 into the equation

y = mx + c

y = -x + c

y = -x + 2

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Answer:

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3 years ago

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What is the value of x? Enter your answer in the box. °

Afina-wow [57]

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Nata [24]

Answer:

Step-by-step explanation:

Given the definite integral $\int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx$ , we to evaluate it. Using integration by substitution method.

Let u = 1-2x⁵ ...1

du/dx = -10x⁴

dx = du/-10x⁴.... 2

Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;

$= \int\limits {\dfrac{x^4}{u^5} } \, \dfrac{du}{-10x^4}$

$= \dfrac{-1}{10} \int\limits {\dfrac{du}{u^5} } \\\\= \dfrac{-1}{10} \int\limits {{u^{-5}du } \\= \dfrac{-1}{10} [{\frac{u^{-5+1}}{-5+1}] \\\\= \dfrac{-1}{10} ({\frac{u^{-4}}{-4})\\\\$