Answer:
Let R = radius of big circle
r=radius of small circle
A1=Area of small circle
A2=Area of big circle
R=9r
A1=50cm^2
A1=pi*r*2
A2=pi*R^2
A2=pi*(9r)^2
A2=81*pi*r^2
A2=81*A1
A2=4050cm^2
Hence the big circle has area of 4050cm^2
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
John is correct as Dividing does not always gets the quantity smaller for example if we divide 4 by 0.5
We get
4/0.5= 8
Answer:
n + 50 = 90; n = 40
Step-by-step explanation:
the angle is a right angle so it adds up to 50
one side is 50
so
n + 50 = 90
subtract 50 to both sides
n = 40
Answer: hello your question is vague hence i will provide a more general answer
Area of a right angled triangle = 1/2 * b * h
Step-by-step explanation:
For a right- angled triangle; the sum of squares of the opposite and adjacent sides = square of the longest side ( i.e. hypothenuse )
hence the Area of a right angled triangle = 1/2 * b * h
where : b = adjacent , h = opposite side
I think motorcycle is the answer.