The geometric rule for the nth term of the geometric sequence for which a1 =−6 and a5=−486 is -6 × 3^(n - 1)
<h3>The nth term of a geometric sequence</h3>
First term, a1 = -6
Fifth term, a5 = -486
a5 = ar^(n - 1)
-486 = -6 × r^(5-1)
-486 = -6r⁴
r⁴ = -486 / 6
r⁴ = 81
r = 4√81
r = 3
Geometric rule:
nth term = ar^(n-1)
nth term = -6 × 3^(n - 1)
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Tan(E) = 6/8 =3/4
tan(E) (opposite side)/(adjacent side)
3x - 2y = 10
10x + 2y = 8 (everything *2)
minus
Therefore final equation is -7x = 2 B
Answer:
A=78
B=102
C=78
Step-by-step explanation:
A= a and 102 are on a straight line so they add up to 180. 180-102=78. The same goes for C
B= the vertical angle for 102, or the same thing with a and c, just flipped around
