Answer:
Step-by-step explanation:
Notice that the series: 1 - 3 + 9 - 27 +... clearly has powers of the factor 3 in its terms and it is also an alternate series (the terms alternate from positive to negative). The terms are positive for 
(even terms) , while the odd terms 
are negative. (so most likely there should be a factor (-1) in the common ratio.
We can then represent it with the following summation expression:
given that each of its first four terms are:
Answer:
Cost of 18 pounds candy = $22.5
Cost of 10 pounds candy = $12.5
Cost of 1 pound of candies = $1.25
Step-by-step explanation:
6 pounds of butterscotch candies cost $7.50
⇔ 1 pound of same candy costs 
$1.25
Now, we need to find the cost of 18 pounds of candy:
as, the cost of 6 pounds candy = $7.50
⇔ Cost of 6 x 3 = 18 pounds candy = $7.50 x 3 = $22.5
Cost of 10 pounds candy = 10 x (Cost of 1 pound candy)
= 10 x ($1.25) = $12.5
The unit rate for butterscotch candies = Cost of 1 pound of candies
= $1.25
the domain of f(x)=9-x^2 is (-∞,∞), {x|x ∈r}
Answer:
456,976,000
Step-by-step explanation:
The total number of possibilities is the product of the number of possibilities in each of the character positions:
10 · 10 · 10 · 26 · 26 · 26 · 26
= 10^3 · 26^4 = 456,976,000
It's not obvious here, but you're being asked to find a linear equation for the velocity of the car, given two points on the line that represents this velocity.
Find the slope of the line segment that connects the points (3 hr, 51 km/hr) and (5 hr, 59 km/hr). Graph this line. Where does this line intersect the y-axis? Find the y-value; it's your "y-intercept," b.
Now write the equation: velocity = (slope of line)*t + b
The units of measurement of "slope of line" must be "km per hour squared," and those of the "y-intercept" must be "km per hour."
Part B: Start with the y-intercept (calculated above). Plot it on the vertical axis of your graph. Now label the horizontal axis in hours: {0, 1, 2, 3, 4, 5, 6}. Draw a vertical line through t=6 hours. It will intercept both the horiz. axis and the sloping line representing the velocity as a function of time. Show only the part of the graph that extends from t=0 hours to t=6 hours.
