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lbvjy [14]
2 years ago
13

How do I factor . X2 { squared } -9x+28?

Mathematics
1 answer:
Dmitrij [34]2 years ago
3 0
It is not factorable
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Factor x3+x2+x+1 by grouping. What is the resulting expression
zmey [24]

Answer:

(x+1) (x^2+1)

Step-by-step explanation:

x^3+x^2+x+1

Factor by grouping

x^3+x^2           +x+1

Factor out x^2 from the first group  and 1 from the second group

x^2( x+1)  + 1( x+1)

Factor out (x+1)

(x+1) (x^2+1)

7 0
3 years ago
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The log: 20 can be written as
adoni [48]

Answer:

10+10

Step-by-step explanation:

3 0
3 years ago
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What is the discontinuity and zero of the function f(x) = the quantity of 3 x squared plus x minus 4, all over x minus 1? A. Dis
Firlakuza [10]

Answer:

The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)  

Step-by-step explanation:

\text{The function is given to be : }f(x)=\frac{3x^2+x-4}{x-1}\\\\\implies f(x)=\frac{(3x+4)(x-1)}{(x-1)}

To find the point of discontinuity :

Put the denominator equal to 0

⇒ x - 1 = 0

⇒ x = 1

Also, if the factor (x - 1) gets cancel, then it becomes a hole rather than a asymptote , ⇒ y = 3x + 4 at x = 1

⇒ y = 7

So, Point of discontinuity : (1, 7)

And the zero is : after cancelling the factor (x - 1) put the remaining factor = 0

⇒ 3x + 4 = 0

⇒ 3x = -4

⇒ x = negative four thirds ( zero of the function)

Therefore, The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)

4 0
3 years ago
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Can two vertical angles form a linear pair?
weqwewe [10]
Adjacent Angles<span> are </span>two angles<span> that share a common vertex, a common side, and no common interior points. (They share a vertex and side, but </span>do<span> not overlap.) A </span>Linear Pair<span> is </span>two<span> adjacent</span>angles<span> whose non-common sides </span>form<span> opposite rays. ... ∠1 and ∠3 are not </span>vertical angles<span> (they are a </span>linear pair<span>).</span>
6 0
3 years ago
Imaginen que un maratonista corre toda una carrera a una velocidad constante. Después de dos horas lleva recorridos 22 km
saw5 [17]

For this case we have:

If after 2 hours the marathon runner has traveled 22 kilometers we have:

2h -----------> 22km

Applying a rule of three, we can know the time it takes to run 42km. So, we have:

2h -----------> 22km

x -------------> 42km

Where "x" is the time it takes to travel 42km. Resolving we have:

x = \frac {(42 * 2)} {22}

x = \frac {84} {22}

x = \frac {42} {11}

x = 3.82 hours

Thus, after 3.82 hours the marathon runner will travel 42km.

Answer:

3.82 hours


6 0
3 years ago
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