The answer is 2 frequencies.
A Full-Duplex QAM 64 K Modem uses two frequencies. One frequency is used for upstream and the other for downstream. A variety of common QAM forms are available and include, 16 QAM, 32 QAM, 64 QAM, and 256 QAM. For example, for domestic broadcast use, 64 and 256 QAM are used for cable modem and digital cable TV. The modulation scheme for this modem uses both amplitude and phase.
Answer: in-basket test
Explanation:
An in-basket test or an in-basket exercise is a test used by firms or governments in recruiting and promoting employees. During the test, job applicants receive some mails, telephone calls, documents and memos.
I guess the correct answer is AND operator
Thе AND οpеratοr is a Bοοlеan οpеratοr usеd tο pеrfοrm a lοgical cοnjunctiοn οn twο еxprеssiοns. AND οpеratοr rеturns a valuе οf TRUЕ if bοth its οpеrands arе TRUЕ, and FALSЕ οthеrwisе.
Answer:
The algorithm to this question as follows:
Algorithm:
finding_small_element(element,Key xa) //defining method that accepts parameter
{
if (element.value>= xa) //check value
{
//skiping node
return;
}
print(element.value);//print value
if (element.left != NULL) //check left node value
{
finding_small_element(element.left,xa); //using method
}
if (element.right != NULL) //check right node value
{
finding_small_element(element.right,xa); //using method
}
}
Explanation:
In the above pre-order traversing algorithm a method "finding_small_element" is defined, that accepts two parameter, that is "element and ax', in which "element" is node value and ax is its "key".
- Inside this if block is used that check element variable value is greater then equal to 0.
- In the next step, two if block is defined, that check element left and the right value is not equal to null, if both conditions are true, it will check its right and left value. In this algorithm, there is no extra need for traversing items.
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