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Helga [31]
3 years ago
8

10.Find the first ICMP Echo Request message that was sent by your computer after you changed the Packet Size in pingplotter to b

e 2000. Has that message been fragmented across more than one IP datagram?
Computers and Technology
1 answer:
Shalnov [3]3 years ago
6 0

Answer:

The message was fragmented across more than one IP datagram

Explanation:

ICMP Echo Request query message is a request sent by a user to a destination system, which then sends an ICMP Echo Reply query message`as a reply.

After I changed the Packet Size in pingplotter to be 2000, the first ICMP Echo Request message that was sent by the computer was:

Flags: 0×01 more fragments.

The message was fragmented across more than one IP datagram

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Which operating system became obsolete with the arrival of more advance graphical user interfaces
jarptica [38.1K]
MS-DOS. MS-DOS stands for Microsoft Disk Operating System. It was the first widely installed operating system for personal computers but became obsolete with the arrival of more advanced graphical user interfaces such as MAC OS developed by Apple, Inc.

Good Luck!
8 0
3 years ago
(5 pt.) The name of a variable in the C programming language is a string that can contain uppercase letters, lowercase letters,
lilavasa [31]

Answer:

The different variable in C is 21213316700.

Explanation:

Given value:

Total value  = letters + underscore value

Total value  = 52 + 1

Total value =53

choice for first character = 53 letters +10 digits

first character = 63

choice for remaining characters

So,

Variable number With one 1 character = 53

Variable number With 2 character  = 53 × 63

Variable number With 3 character = 53 × 63²

Variable number With 4 character  = 53 × 63³

.

.

.

Variable number With 7 character  = 53 \times  63^{7}

Total difference variable = 53 + 53 × 63+ 53 × 63²+ 53 × 63³+....+ 63^{7}

Total difference variable = 53(1 + 63 + 63²+ 63³+ .... + 63^{7})

Formula:

1+x+x^2+x^3+x^4+........x^n\\\\\Rightarrow  \frac{x^{(n+1)} -1}{x-1}

Total difference variable

53 \times \frac{63^{7+1} -1 }{63-1}\\\\53 \times \frac{63^{8} -1 }{63-1} \\\\ \therefore 63^8 = 2.48 \times 10^{14}\\\\53 \times \frac{2.48 \times 10^{14} -1  }{62}\\\\53 \times \frac{1.48 \times 10^{14}}{62}\\\\21213316700

6 0
4 years ago
You need to view the contents of /var/log/auth.log to get information about the users that have been logging on to the system. T
leva [86]

Answer:

more /var/log/auth.log

less /var/log/auth.log

Explanation:

The commands that can be used to view the content of the auth.log file page by page are:

more /var/log/auth.log

less /var/log/auth.log

5 0
3 years ago
Although “dog.jpg” and “dog.JPG” and “Dog.jpg” and “DOG.JPG” all appear to be the same file, they are not considered the same wh
____ [38]
Because of the capitalization; when talking about computer science and programming things have to be very tedious and specific. <span />
5 0
3 years ago
How can an exception be explicitly raised in C++? How are exceptions bound to handlers in C++?
xenn [34]

Answer:

Exceptions are raised using throw statement in c++.

Explanation:

Try block is used to keep the statements which we felt that they will raise an exception. Catch block is used to catch the exception which is thrown by the try block.

#include<iostream.h>

void main(){

int x,y,z;

try{

cout<"enter 2 numbers";

cin>>x>>y;

if(y==0)

throw y;

z=x/y;

}

catch(int x){

cout<<"exception caught";

}

}

4 0
3 years ago
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