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erik [133]
4 years ago
13

For each expression,use a property to write an equivalent expression.Tell which property you used. 10:CD= 11:x+13= 12:4(2x-3)= 1

3:2+(a+b)= 14:Draw algebra time models to prove that 4+8x and 4(2x+1) are equivalent.

Mathematics
1 answer:
stellarik [79]4 years ago
4 0
10.) DC 
community property

11.) 13+x
community property


12.) 8x-12
distributive property

13.)  (2+a)+b


14.) 4(2x+1)= 4+8x

For question 14 you can do 4×2=8x. Then do 4×1=4. It is equal. Just do distributive property for number 14 for 4(2x+1)



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harina [27]
If you meant a thickness of 1/2 inch. . .
Because the inserts are put on all the sides, the dimensions of the usable space are 5 X 5 X 9.  This means the diameter of the base is 5.  The radius is half the diameter, so we divide 5 by 2 to get the radius.  5/2 = 2.5.  Now, we plug in the radius and the height (9) into the formula for the volume of a cylinder, which is volume= \pi  r^{2} h

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6 0
3 years ago
A sample of 11001100 computer chips revealed that 62b% of the chips fail in the first 10001000 hours of their use. The company's
STALIN [3.7K]

Answer:

Rule

If;

P-value > significance level --- accept Null hypothesis

P-value < significance level --- reject Null hypothesis

Z score > Z(at 90% confidence interval) ---- reject Null hypothesis

Z score < Z(at 90% confidence interval) ------ accept Null hypothesis

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

z score = 1.35

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

Question; A sample of 1100 computer chips revealed that 62% of the chips fail in the first 1000 hours of their use. The company's promotional literature states that 60% of the chips fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that fail is different from the stated percentage. Determine the decision rule for rejecting the null hypothesis, H0, at the 0.10 level.

Step-by-step explanation:

Given;

n=1100 represent the random sample taken

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

Test statistic z score can be calculated with the formula below;

z = (p^−po)/√{po(1−po)/n}

Where,

z= Test statistics

n = Sample size = 1100

po = Null hypothesized value = 0.60

p^ = Observed proportion = 0.62

Substituting the values we have

z = (0.62-0.60)/√{0.60(1-0.60)/1100}

z = 1.354

z = 1.35

To determine the p value (test statistic) at 0.01 significance level, using a two tailed hypothesis.

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

3 0
4 years ago
PLEASE HELP ME 10 POINTS
Furkat [3]
B is 3, m is 0.75 x is number of miles
5 0
3 years ago
Tyler has at most $20 to spend on rides and games at the carnival. Each ride costs $0.75 and each game costs $0.50. Which inequa
GaryK [48]

Answer:

The inequality that can be used to determine how many rides r and games g Tyler can pay for at the carnival is:

0.75r+0.50g≤20, where:

r is the number of rides

g is the number of games

Step-by-step explanation:

With the information provided, you can say that the amount spent at the carnival is equal to the cost per ride for the number of rides plus the cost per game for the number of games. Also, given that the statement indicates that Tyler has at most $20, the inequality would indicate that the amount spent has to be less than or equal to 20. According to this, the inequality that can be used to determine how many rides r and games g Tyler can pay for at the carnival is:

0.75r+0.50g≤20, where:

r is the number of rides

g is the number of games

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4 years ago
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