Remember
i²=-1 so
i³=-i
i⁴=1
so
5i⁴+2i³+8i²-4
5(1)+2(-i)+8(-1)-4
5-2i-8-4
-7-2i is the form
Answer:
420 ways
Step-by-step explanation:
According to the given statement:
We want to divide the 10 dogs into three groups, one with 3 dogs, one with 5 dogs, and one with 2 dogs. How many ways can we form the groups such that fluffy is in the 3-dog group and nipper is in the 5-dog group.
In this way we have 8 dogs left.
2 spaces left in 3 dogs group
4 spaces left in 5 dogs group
and 2 spaces in 2 dogs group
Therefore:
= 8!/2!4!2!
= 8*7*6*5*4*3*2*1/2*4*3*2*2
= 8*7*6*5/2*2
= 1680/4
=420
It means there are 420 ways to from the groups....
A right angle is 90 degree, and all the three angles make a sum of 180, so the two acute angles will always add up to be 90
Answer:
8+24x^8
Step-by-step explanation:
