Answer:
Apparent power is 1.413Volt-Amps.
Step-by-step explanation:
We are given that in a parallel circuit,
,R=33kΩ and 
=82kΩ.
And we are asked to find apparent power.
Apparent power is the combination of true power and reactive power.
In other words, we can say that in a power triangle apparent power is the hypotenuse where as true power and reactive powers are sides.
Let us find true power , reactive power first and the using Pythagorean theorem we can find apparent power.
True power=
Reactive power=
Hence apparent power=
Initial is 200
Amount deposited each month = d
Current equation is '200 + 5d'
We know he gets a cheque worth 3x what he has so far, so 3*(200+5d) = 600+15d
He adds this to what he has, do 200 + 5d + 600 +15d, or simply
800 + 20d
We know that this amount is 300 more than the amount be needs (3000), so 800 + 20d = 3000 + 300, or
800 + 20d = 3300
Subtract 800 from both sides, to get
20d = 2500
Divide both sides by 20 to isolate d, so you end up with
d = 125
He deposits $125 per month
It depends on what context the information is used in. All of the above statements could be correct but because we don’t know the context of the information there is no way to decide which statement is truly correct
His total pay was $997.
We use the equation
y=150+0.14x
to represent this, were y is his total pay and x is the amount of sales he has. Using our information, we have
y=150+0.14(6050) = 150+847 = 997
Answer:
I got (y-7)=1/13(x+6) for point slope
and y=1/3x+13 for slope intercept form
double check me though I'm new at this
