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Andrews [41]
3 years ago
10

Find the sum and choose the correct answer.

Mathematics
2 answers:
MrRa [10]3 years ago
8 0
Hi

2n³ + 4n² - 7 + (-n³ - 8n - 2) = 2n³ - n³ + 4n² - 8n - 7 - 2 

n³ + 4n² - 8n - 9

Answer: n³ + 4n² - 8n - 9
Vaselesa [24]3 years ago
7 0

Answer:

Correct answer is:

n³+4n²-8n-9

Step-by-step explanation:

We have to find the sum of:

2n³ + 4n² - 7  and  -n³ - 8n - 2

On adding both terms:

2n³ + 4n² - 7 + (-n³ - 8n - 2)

= 2n³ - n³ + 4n² - 8n - 7 - 2

= n³+4n²-8n-9

Hence, sum of 2n³ + 4n² - 7  and  -n³ - 8n - 2 is:

n³+4n²-8n-9

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Since we’re trying to find minutes, concert all known information to minutes

1 hr 15 mins = 75 mins
1 hr 30 mins = 90 mins

Next, calculate how many total minutes Gage has skated in the first 8 days

75(5) + 90(3) = 645 mins

Create an equation to find the average of Gage’s minutes of skating. Add up all the minutes and divide by the total amount of days and set equal to 85, the average we are trying to get.

(645 mins + x mins)/9 days = 85

Solve for x

645 + x = 765
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Answer:

Step-by-step explanation:

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2 years ago
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aleksklad [387]

Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

Step-by-step explanation:

a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

  • 1st quarter-2
  • 2nd quarter-9
  • 3rd quarter-7
  • 4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4

Hence, there are 4 more home goals than away goals.

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