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3 years ago

Help me please and ty

Mathematics

1 answer:

pav-90 [236]3 years ago

3 0

Answer: 3m

And I had to write something for this to be ong enough so thats what this is:)

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John has $900 in his bank account and plans to withdraw $75 per month. Write a linear equation for this situation and determine

Iteru [2.4K]

Answer:

I think the answer is y=-75x+900 ; 12 months

8 0

3 years ago

Read 2 more answers

The length of a photograph is 1 cm less than twice the width. The area is 91cm^2. find the width and length.

maksim [4K]

Answer:

Width=6.5 cm

Length=12 cm

Step-by-step explanation:

Step 1: Express the lengths and widths

Width=w

Length=l, but 1 cm less than twice the width=(2×w)-1=2 w-1

Step 2: Solve for the length and width

A=L×W

where;

A=area of the photograph

L=length of the photograph

W=width of the photograph

In our case;

A=91 cm²

L=2 w-1

W=w

91=(2 w-1)w

2 w²-w=91

2 w²-w-91=0, is a quadratic equation

solve for w

w={-1±√(-1²-4×2×-91)}/(2×2)

w=(-1±27)/4

w=(27-1)/4=6.5, or (-1-27)/4=-8

Take w=6.5 cm

L=(2×6.5)-1=13-1=12 cm

Width=6.5 cm

Length=12 cm

6 0

3 years ago

Determine the equation of the circle graphed below. ( please help me )

Brums [2.3K]

Answer:

$Equation : \\(x+3)^2 + ( y -2)^2 = 36$

Step-by-step explanation:

For standard form the circle's equation we need the centre of the circle and the radius.

Step 1: Find the centre

If the centre is not given find the end points of the diameter

and then find the mid point.

Let the end points of the diameter be : ( - 3 , 8 ) and ( -3 , -4 )

The mid-point of the diameter is :

$Mid-point = (\frac{-3 + - 3}{2}, \frac{-4+8}{2}) = (-3, 2)$

Therefore, centre of the circle = ( -3 , 2 )

Step 2 : Find radius

$Radius = \frac{Diameter }{2}$

Diameter is the distance between the end points ( -3 , 8) and ( -3 , -4 )

That is ,

$Diameter = \sqrt{(-3-(-3))^2 + ( -4 -8)^2}\\$

$= \sqrt{(-3 + 3)^2 + (-12)^2}\\\\=\sqrt{0 + 144}\\\\=12$

Therefore ,

$Radius = \frac{12}{2} = 6$

Step 3 : Equation of the circle

Standard equation of the circle with centre ( h ,k )

and radius ,r is :

$(x - h)^2+(y -k)^2 = r^2$

Therefore, the equation of the circle with centre ( -3, 2)

and radius = 6 is :

$(x - (-3))^2 + (y - 2)^2 = 6^2\\\\(x + 3)^2 + (y - 2)^2 = 36$

5 0

2 years ago

Compare the ratio of the longest side being 14 1/2 to shortest side 1 1/4 and turn it into a simplified fraction

marusya05 [52]

(14 1/2)/(1 1/4) change both to improper fractions

(29/2)/(5/4) invert second function (or the denominator fraction) and multiply.

(29/2)*(4/5) multiply...

58/5 change improper fraction back to mixed fraction

11 3/5 or a decimal 11.6

4 0

3 years ago

Angie has to fill in a reading log for her English class. She is required to read a total of 10 and 5 over six hours a week. On

JulijaS [17]

Given:

She is required to read a total = $10\dfrac{5}{6}$ hours a week.

Monday she read $1\dfrac{1}{3}$ hours.

Tuesday she read $\dfrac{3}{4}$ of an hour.

Thursday she read 3 hours.

To find:

The total hours does she still need to read in order to get full credit.

Solution:

Total time = $10\dfrac{5}{6}$ hours a week.

Total time she already read $=1\dfrac{1}{3}+\dfrac{3}{4}+3$ hours

$=\dfrac{1\times 3+1}{3}+\dfrac{3}{4}+3$ hours

$=\dfrac{4}{3}+\dfrac{3}{4}+3$ hours

$=\dfrac{16+9+36}{12}$ hours

$=\dfrac{61}{12}$ hours

Now,

Remaining time = Total time - Total time she already read

$=10\dfrac{5}{6}-\dfrac{61}{12}$

$=\dfrac{65}{6}-\dfrac{61}{12}$

$=\dfrac{130-61}{12}$

$=\dfrac{69}{12}$

$=\dfrac{23}{4}$

$=5\dfrac{3}{4}$

Therefore, the required time is $5\dfrac{3}{4}$ hours.

8 0

3 years ago