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Tanya [424]
3 years ago
10

The scale of a model train is 1 inch to 13.5 ft. One of the cars of the model train is 5inches long. What is the length in feet

of the actual train csr
Mathematics
1 answer:
aleksklad [387]3 years ago
7 0

Answer:

The length of the actual train's car is <u>67.5 feet.</u>

Step-by-step explanation:

Given:

The scale of a model train is 1 inch to 13.5 ft.

Now, to get the length of the actual car of the train.

Let the length of actual train's car be x.

And, the length of the car of model train = 5\ inches\ long.

<em>According to the scale of the model train, 1 inch is equivalent to 13.5 ft. </em>

<em>Thus, 5 inches is equivalent to </em>x.<em />

Now, to get the length of actual train's car using cross multiplication method:

\frac{1}{13.5} =\frac{5}{x}

By cross multiplying we get:

x=67.5\ feet.

Therefore, the length of the actual train's car is 67.5 feet.

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3 years ago
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Avery can run at 10 uph. The bank of a river is represented by the line 4x + 3y = 12, and Avery is at (7, 5). How much time does
Reil [10]
The minimum distance will be along a perpendicular line to the river that passes through the point (7,5)

4x+3y=12

3y=-4x+12

y=-4x/3+12/3

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y=3x/4+b, and we need it to pass through (7,5) so

5=3(7)/4+b

5=21/4+b

20/4-21/4=b

-1/4=b so the perpendicular line is:

y=3x/4-1/4

So now we want to know the point where this perpendicular line meets with the river bank.  When it does y=y so we can say:

(3x-1)/4=(-4x+12)/3  cross multiply

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y=(3x-1)/4

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y=1.28

So now that we know the point on the river that is closest to Avery we can calculate his distance from that point...

d^2=(x2-x1)^2+(y2-y1)^2

d^2=(7-2.04)^2+(5-1.28)^2

d^2=38.44

d=√38.44

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Since he can run at 10 uph...

t=d/v

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So it will take him 0.62 hours or 37 minutes and 12 seconds for him to reach the river.




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7nadin3 [17]

Answer: 3,750 miles

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3 years ago
What is the property of 6x=72?
Andreyy89

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In this case, you have to do division.

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Hope this helps :)

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