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PSYCHO15rus [73]
3 years ago
12

Determine the input value for which the statement

Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0

Answer:

The x-value at which the two functions' values are equal is 5.

Step-by-step explanation:

Let f(x) = 3 and g(x) = x-2, if f(x) = g(x), then:

x - 2 = 3

x = 3+2

x = 5

The x-value at which the two functions' values are equal is 5.

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alexandrea and imani each think of a number. alexandras number is 8 more than Imanis number. the sum of two numbers is 50. what
juin [17]
Alexandera=a
imani=i

a is 8 more than i or
a=8+i

the sum of the 2 numbers is 50 or
a+i=50

a=8+i
so subsitute 8+i for a in a+i=50
8+i+i=50
8+2i=50
subtract 8 from both sides
2i=42
divide both sides by 2
i=21

subsiutte into a=8+i

a=8+21
a=29



a=29
i=21
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3 years ago
I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.
elena-14-01-66 [18.8K]

Hello,

m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\

cos(30^o)=\dfrac{\sqrt{3} }{2} \\

In the triangle ABC,

cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\

sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}

In the triangle ACB,

cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\

6 0
2 years ago
Mrs. Hartill drove 3.1 miles to the grocery store, then 4.25 miles to the salon, and 10.8 miles to her sons house. How many mile
Bad White [126]

Answer: 18.15 miles

Step-by-step explanation:

8 0
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Given that a = -1, b=2 and c= -3 ,find the value of a(b2+c2)
KiRa [710]

Answer:

a(b^{2}+c^{2}) = = -13

Step-by-step explanation:

Given that a = -1, b=2 and c= -3

find the value of a(b^{2}+c^{2})

Just substitute the values given for each variable

a(b^{2}+c^{2}) = (-1)(2^{2}+(-3)^{2}) ; do the exponents first

a(b^{2}+c^{2}) = (-1)(4+9)=(-1)(13) ; now add inside the parenthesis;

a(b^{2}+c^{2}) = -13 ; and multiply by -1

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The answer is D. You’d need to minus the area of the circle away from the area of the triangle to get the area of the shaded region
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