Answer:
y=-2/3 x +4
Step-by-step explanation:
slop = (6-0)/(-3-6)= -2/3
c= 4 (when x =0)
line equation:
y= mx + c
y=-2/3 x +4
Answer:
The best estimate for the solution is the ordered pair 
Step-by-step explanation:
we have
------> equation A
------> equation B
we know that
using a graphing tool, the solution of the system of equations is the intersection point both graphs
The intersection point is 
therefore
The best estimate for the solution is the ordered pair
Answer:
As the first part comes to the rest means, then it will fall under gravity directly.
First of all maximum height,
H=
g
u²sin²θ
H=
2×10
400×(
2
1
)
H=10m.
As initially the full projectile was supposed to land at A but due to explosion first part land at A', so to make the centre of mass lies at A the second part should lie at B.
f they don't break (explode) range OA
OA=
g
u²sin2θ
OA=400×sin45×
10
2
So, given a quadratic function, y = ax2<span> + bx + c, when "a" is positive, the </span>parabola<span> opens upward and the vertex is the </span>minimum<span> value. On the other hand, if "a" is negative, the graph opens </span>downward<span> and the vertex is the </span>maximum<span> value. To put it in complicated terms. Or when A is positive the graph is shaped like a U but if A is negative the graph is an upside down U
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