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Alex Ar [27]
3 years ago
5

Sarah rolls a die twice. What is the probability that she rolls a 3 and then an even number?

Mathematics
1 answer:
egoroff_w [7]3 years ago
7 0
1/12

This is because she has a 1/6 chance of getting a 3 on the first try and then a 1/2 chance of getting an even on the second. Multiply these two together to get your answer. 
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Please help thank u.
Sever21 [200]

Answer:

-4, 3 1/2 JFURE8EGNRODG RE NEJEUSUEHEUE I did this for 20 characters

4 0
3 years ago
Suppose you received a score of 95 out of 100 on exam 1 . The mean was 79 and the standard deviation was 8 . If your score on ex
Schach [20]

Answer:

You did the same on both exams.

Step-by-step explanation:

To compare both the scores, we need to compute the z scores of both the exams and then compare the values. The formula for z-score is:

<u>Z = (X - μ)/σ</u>

Where X = score obtained

           μ = mean score

           σ = standard deviation

For Exam 1:

Z = (95 - 79)/8

  = 16/8

<u>Z = 2</u>

For Exam 2:

Z = (90 - 60)/15

  = 30/15

<u>Z = 2</u>

<u>The z-scores for both the tests are same hence the third option is correct i.e. </u><u>you did the same on both exams.</u>

8 0
3 years ago
Whats 20.5833333333 in fraction form
Effectus [21]
It should be 20 7/12
3 0
3 years ago
PLEASE HELP ILL GIVE BRAINLY <br><br><br> True or false: you can collect data yourself?
cluponka [151]

Answer:

true

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Let y′′′−9y′′+20y′=0. find all values of r such that y=erx satisfies the differential equation. if there is more than one correc
DerKrebs [107]

we are given

differential equation as

y'''-9y''+20y'=0

we are given

y=e^{rx}

Firstly, we will find y' , y'' and y'''

those are first , second and third derivative

First derivative is

y'=re^{rx}

Second derivative is

y''=r*re^{rx}

y''=r^2e^{rx}

Third derivative is

y'''=r^2*re^{rx}

y'''=r^3e^{rx}

now, we can plug these values into differential equation

and we get

r^3 e^{rx}-9r^2 e^{rx}+20re^{rx}=0

now, we can factor out common terms

e^{rx}(r^3 -9r^2 +20r)=0

we can move that term on right side

(r^3 -9r^2 +20r)=0

now, we can factor out

r(r^2 -9r +20)=0

r(r-5)(r-4)=0

now, we can set them equal

r=0

r-5=0

r=5

r-4=0

r=4

so, we will get

r=0,4,5...............Answer

4 0
3 years ago
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