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Tanzania [10]
3 years ago
10

There are eight different jobs in a printer queue. Each job has a distinct tag which is a string of three upper case letters. Th

e tags for the eight jobs are:
{LPW,QKJ,CDP,USU,BBD,PST,LSA,RHR}

a. How many different ways are there to order the eight jobs in the queue?
b. How many different ways are there to order the eight jobs in the queue so that job USU comes immediately before CDP?
c. How many different ways are there to order the eight jobs in the queue so that job USU comes somewhere before CDP in the queue, although not necessarily immediately before?
d. How many different ways are there to order the eight jobs in the queue so that either QKJ or LPW come last?
e. How many different ways are there to order the eight jobs in the queue so that QKJ is either last or second-to-last?
Mathematics
1 answer:
N76 [4]3 years ago
3 0

Answer:

a. 40320 ways

b. 10080 ways

c. 25200 ways

d. 10080 ways

e. 10080 ways

Step-by-step explanation:

There are 8 different jobs in a printer queue.

a. They can be arranged in the queue in 8! ways.

No. of ways to arrange the 8 jobs = 8!

                                                        = 8*7*6*5*4*3*2*1

No. of ways to arrange the 8 jobs = 40320 ways

b. USU comes immediately before CDP. This means that these two jobs must be one after the other. They can be arranged in 2! ways. Consider both of them as one unit. The remaining 6 together with both these jobs can be arranged in 7! ways. So,

No. of ways to arrange the 8 jobs if USU comes immediately before CDP

= 2! * 7!

= 2*1 * 7*6*5*4*3*2*1

= 10080 ways

c. First consider a gap of 1 space between the two jobs USU and CDP. One case can be that USU comes at the first place and CDP at the third place. The remaining 6 jobs can be arranged in 6! ways. Another case can be when USU comes at the second place and CDP at the fourth. This will go on until CDP is at the last place. So, we will have 5 such cases.

The no. of ways USU and CDP can be arranged with a gap of one space is:

6! * 6 = 4320

Then, with a gap of two spaces, USU can come at the first place and CDP at the fourth.  This will go on until CDP is at the last place and USU at the sixth. So there will be 5 cases. No. of ways the rest of the jobs can be arranged is 6! and the total no. of ways in which USU and CDP can be arranged with a space of two is: 5 * 6! = 3600

Then, with a gap of three spaces, USU will come at the first place and CDP at the fifth. We will have four such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 4 * 6!

Then, with a gap of four spaces, USU will come at the first place and CDP at the sixth. We will have three such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 3 * 6!

Then, with a gap of five spaces, USU will come at the first place and CDP at the seventh. We will have two such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 2 * 6!

Finally, with a gap of 6 spaces, USU at first place and CDP at the last, we can arrange the rest of the jobs in 6! ways.

So, total no. of different ways to arrange the jobs such that USU comes before CDP = 10080 + 6*6! + 5*6! + 4*6! + 3*6! + 2*6! + 1*6!

                    = 10080 + 4320 + 3600 + 2880 + 2160 + 1440 + 720

                    = 25200 ways

d. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways. Similarly, if LPW comes last, the remaining 7 jobs can be arranged in 7! ways. so, total no. of different ways in which the eight jobs can be arranged is 7! + 7! = 10080 ways

e. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways in the queue. Similarly, if QKJ comes second-to-last then also the jobs can be arranged in the queue in 7! ways. So, total no. of ways to arrange the jobs in the queue is 7! + 7! = 10080 ways

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Help find the answer for problem number 4
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3 years ago
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Read 2 more answers
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defon
Part A

The equation is b = 36*a or simply b = 36a

We take the size of the farm 'a' and multiply it by 36 to get the number of bushels of corn 'b'.

-----------------------------------

Part B

The 36 means there are 36 times more bushels of corn compared to the size of the farm in acres

For example, if the size is 2 acres then 
b = 36*a
b = 36*2
b = 72
yielding 72 bushels of corn

-----------------------------------

Part C

Along the first row you should have: 25 and 30 in the missing blanks (over 900 and 1080 respectively)

You find this by dividing the value of b over 36
eg: b/36 = 900/36 = 25

-------

Then along the bottom row you should have the following for the blanks: 0, 360, 1800

These values are found by multiplying the 'a' value by 36
eg: if a = 10 then b = 36*a = 36*10 = 360

-----------------------------------

Part D

Plot any two points you want from the table back in part C
So plot say (0,0) and (10,360). Then draw a straight line through those two points.

-----------------------------------

Part E

The point (30,1080) means a = 30 and b = 1080
So if the farm is 30 acres, then it can produce 1080 bushels of corn

Notice how
b = 36*a
b = 36*30 <<-- replace 'a' with 30
b = 180
And how this matches up with the fourth column of the table in part C. So you can use this part to get a hint of how to fill out the table (or at least know what one column looks like)


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