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tatuchka [14]
3 years ago
5

How does place value help me subtract decimals

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
8 0
okay make sure you write this down on your paper place value help me subtract decimals because if you want you don't line up the decimals you'll get the right answer . but if you do line up the decimals you'll get the wrong answer so you do not line up decimals when you are subtracting decimals
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Help me for f???????????
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The number decreases. 
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3 years ago
A cylinder has a height of 12 inches and a radius of 1.5 inches. What is its voulme? Round your answer to the nearest tenth. Use
Lerok [7]

Answer:

It's volume is of 84.78 cubic inches.

Step-by-step explanation:

Volume of a cylinder:

The volume of a cylinder with radius r and height h is given by:

V = \pi r^2h

A cylinder has a height of 12 inches and a radius of 1.5 inches.

This means that h = 12, r = 1.5

What is its volume?

V = \pi r^2h = 3.14(1.5)^2(12) = 84.78

It's volume is of 84.78 cubic inches.

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2 years ago
Someone please help me with this geometry question
shutvik [7]

Answer:

A parallelogram

Step-by-step explanation:

The opposite sides and angles are congruent.

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3 years ago
Read 2 more answers
What is the sum of a number n and 4 is no more than 13
posledela
N+4=13
   -4   -4
n = 9

the sum of a number(n) and 4 that is no larger than 13 is 9
8 0
3 years ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

4 0
3 years ago
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