The first figure has 3 line segments.
the second figure has 3+3 =3*2 = 6 line segments
the third figure has 3+3+3 = 3*3 = 9 line segments
the fourth figure has 3+3+3+3=3*4=12 line segments...
so it is clear that:
the 20th figure has 3*20=60 line segments.
Answer: 60
Step-by-step explanation:
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Answer:
They would need to sell more than or equal to 140 boxes of cookies.
Step-by-step explanation:
The equation would be
2.50t >= 350
-------- -------
2.50 2.50
t >= 140
Answer:
maximum height is 4.058 metres
Time in air = 0.033 second
Step-by-step explanation:
Given that the equation height h
h = -212t^2 + 7t + 4
What is the toy's maximum height?
Let us assume that the equation is a perfect parabola
Time t at Maximum height will be
t = -b/2a
Where b = 7 and a = - 212
t = -7/ - 212 ×2
t = 7/ 424 = 0.0165s
Substitute t in the main equation
h = - 212(7/424)^2 + 7(7/424) + 4
h = - 0.05778 + 0.115567 + 4
h = 4.058 metres
Therefore the maximum height is 4.058 metres
How long is the toy in the air?
The object will go up and return to the ground.
At ground level, h = 0
-212t^2 + 7t + 4 = 0
212t^2 - 7t - 4 = 0
You can factorize the above equation and pick the positive time t since time can't be negative
Or
Since we have assumed that it's a perfect parabola,
Total time in air = (-b/2a) × 2
Time in air = 0.0165 × 2 = 0.033 s
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