Answer:
99%, because as the level of confidence increases, Zc increases.
Step-by-step explanation:
Answer:
n<50
Step-by-step explanation:
7/2*5n + 14<49
7n/2*5+14<49
(7n)+(2*5)14/2*5 <49
7n+10*14/2*5 <49
7n+140/2*5 <49
7n+140/10 <49
7n+140 < 10*49
7n+140 < 490
(7n+140)+(-140)<490+(-140)
7n+140-140<490-140
7n<350
7n/7 < 350/7
n<2*5^2*7/7
n<2*5^2
n<2*25
n<50
Answer:
<h2>89.7</h2>
Step-by-step explanation:
Do you mean 130% of 69? If so then we multiply 69 by 1.3. The answer is 89.7. If you mean something else, please state your question more clearly and I'll be happy to answer it.
<h2>I'm always happy to help :)</h2>
Answer:
29.5+/-1.11
= ( 28.39, 30.61)
Therefore, the 90% confidence interval (a,b) =( 28.39, 30.61)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = 29.5
Standard deviation r = 5.2
Number of samples n = 59
Confidence interval = 90%
z-value (at 90% confidence) = 1.645
Substituting the values we have;
29.5+/-1.645(5.2/√59)
29.5+/-1.645(0.676982337100)
29.5+/-1.113635944529
29.5+/-1.11
= ( 28.39, 30.61)
Therefore, the 90% confidence interval (a,b) =( 28.39, 30.61)
