Prove: The midsegment between sides Line segment AB and Line segment BC is parallel to side Line segment AC.
1 answer:
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The first one is B because of the first attachment. The second one is A because of the second attachment. The third one is C because of the expression used to solve for sum of angles:
(n-2)180
(8-2)180
1080
Hope this helps!
(n-2)180
(8-2)180
1080
Hope this helps!
Answer: I have the pictures attached
Step-by-step explanation:
In order to graph this, we have to get it into this equation: y = mx + b, where m = slope and b = y intercept.
y = 3/2x - 4 is already in this form.
2y + 4 = 2 + 3x is not, so we have to isolate y
2y + 4 - 4 = 2 + 3x - 4
2y = -2 + 3x
2y/2 = -2/2 + 3x/2
y = -1 + 3/2x
y = 3/2x - 1
Okay, now graph it knowing your y intercepts and your slopes.
