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Flura [38]
3 years ago
11

Is (6/5, 2) a solution to y = x + 4/5​

Mathematics
2 answers:
steposvetlana [31]3 years ago
5 0

Answer:

Yes, it is.

Step-by-step explanation:

y = x + 4/5

2 = 6/5 + 4/5

2 = 10/5

2 = 2

Two equals two.

Ray Of Light [21]3 years ago
5 0
No, it is not. We know ordered pairs go like this: (x, y). If x is equal to 6.5, then we can do 6.5 + 4.5, which equals 11. If x is 6.5, then y should be 11, not 2.
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The area of the following composite figure is 74 square inches. What is the value of b
oee [108]
It is the last choice, 12
seven times two is 14
74-14=60
60/5=12
Hope this helps!!
5 0
3 years ago
Need Help<br>*Please Show Work*​
sergejj [24]

Hi there! :)

Answer:

y = -2x + 3

Step-by-step explanation:

We can write an equation in slope-intercept form. Use the slope formula to find the rate of change in the table:

m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}

Plug in values from the table:

m  = \frac{5 - 7}{-1 - (-2)}

Simplify:

m = -2 (rate of change)

Use a point from the table (-2, 7) and the slope to solve for the equation for the linear function:

7 = -2(-2) + b

7 = 4 + b

7 -4 = b

b = 3

Rewrite:

y = -2x + 3 is the equation for the linear function.

8 0
4 years ago
1) 2x^2+x-5m=0
german

Answer:

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6 0
3 years ago
Read 2 more answers
A tank holds 300 gallons of water and 100 pounds of salt. A saline solution with concentration 1 lb salt/gal is added at a rate
Shkiper50 [21]

The amount of salt in the tank changes with rate according to

Q'(t)=\left(1\dfrac{\rm lb}{\rm gal}\right)\left(4\dfrac{\rm gal}{\rm min}\right)-\left(\dfrac{Q(t)}{300+(4-1)t}\dfrac{\rm lb}{\rm gal}\right)\left(1\dfrac{\rm gal}{\rm min}\right)

\implies Q'+\dfrac Q{300+3t}=4

which is a linear ODE in Q(t). Multiplying both sides by (300+3t)^{1/3} gives

(300+3t)^{1/3}Q'+(300+3t)^{-2/3}Q=4(300+3t)^{1/3}

so that the left side condenses into the derivative of a product,

\big((300+3t)^{1/3}Q\big)'=4(300+3t)^{1/3}

Integrate both sides and solve for Q(t) to get

(300+3t)^{1/3}Q=(300+3t)^{4/3}+C

\implies Q(t)=300+3t+C(300+3t)^{-1/3}

Given that Q(0)=100, we find

100=300+C\cdot300^{-1/3}\implies C=-200\cdot300^{1/3}

and we get the particular solution

Q(t)=300+3t-200\cdot300^{1/3}(300+3t)^{-1/3}

\boxed{Q(t)=300+3t-2\cdot100^{4/3}(100+t)^{-1/3}}

5 0
3 years ago
Write 0.323 as a fraction in simplest form.
Ugo [173]

Answer:323/1000

Step-by-step explanation:

4 0
3 years ago
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