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Flura [38]
3 years ago
11

Is (6/5, 2) a solution to y = x + 4/5​

Mathematics
2 answers:
steposvetlana [31]3 years ago
5 0

Answer:

Yes, it is.

Step-by-step explanation:

y = x + 4/5

2 = 6/5 + 4/5

2 = 10/5

2 = 2

Two equals two.

Ray Of Light [21]3 years ago
5 0
No, it is not. We know ordered pairs go like this: (x, y). If x is equal to 6.5, then we can do 6.5 + 4.5, which equals 11. If x is 6.5, then y should be 11, not 2.
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The price of a television decreased from $275 to $190 during a clearance sale. What is the percent of decrease in the price? Rou
just olya [345]
195=275-275p -275 -27 -80=-275p You do -80 divided by -175 which is 0.45 and your answer is C45%.
3 0
3 years ago
100 Points
kakasveta [241]

Answer:

Step-by-step explanation:

f(-x) is a reflection of f(x) in the y-axis

3 0
3 years ago
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If a rectangle has length x and width x-2, what is the perimeter of the rectangle in terms of x?​
ivolga24 [154]

Answer:

length x and width x-2

perimeter of rectangle=2[l+b]=2[(x-2)+x]=4x-4 is your answer

6 0
3 years ago
Find the percent of decrease from 280 to 210. Round to the nearest tenth of a percent, if necessary.
Vlada [557]
To find the decreased percentage,here's what we can do:
\frac{originl \: value - new \: value}{originl \: value}  \times 100\%

In this case,the eqaution would be:
\frac{280 - 210}{280}  \times 100\% \\  =  \frac{70}{280}  \times 100\% \\  =  \frac{1}{4}  \times 100\% \\  = 25\%
Hope it helps!
5 0
3 years ago
A small regional carrier accepted 23 reservations for a particular flight with 20 seats. 14 reservations went to regular custome
MrRissso [65]

Answer:

- The probability that overbooking occurs means that all 8 non-regular customers arrived for the flight. Each of them has a 56% probability of arriving and they arrive independently so we get that  

P(8 arrive) = (0.56)^8 = 0.00967

- Let's do part c before part b. For this, we want an exact booking, which means that exactly 7 of the 8 non-regular customers arrive for the flight. Suppose we align these 8 people in a row. Take the scenario that the 1st person didn't arrive and the remaining 7 did. That odds of that happening would be (1-.56)*(.56)^7.

Now take the scenario that the second person didn't arrive and the remaining 7 did. The odds would be  

(0.56)(1-0.56)(0.56)^6 = (1-.56)*(.56)^7. You can run through every scenario that way and see that each time the odds are the same. There are a total of 8 different scenarios since we can choose 1 person (the non-arriver) from 8 people in eight different ways (combination).  

So the overall probability of an exact booking would be [(1-.56)*(.56)^7] * 8 = 0.06079

- The probability that the flight has one or more empty seats is the same as the probability that the flight is NOT exactly booked NOR is it overbooked. Formally,  

P(at least 1 empty seat) = 1 - P(-1 or 0 empty seats)  

= 1 - P(overbooked) - P(exactly booked)

= 1 - 0.00967 - 0.06079  

= 0.9295.

Note that, the chance of being both overbooked and exactly booked is zero, so we don't have to worry about that.

Hope that helps!

Have a great day :P

7 0
3 years ago
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