A. -9v – 9 = -27 thats question 1

Mathematics

1 answer:

jeka943 years ago

6 0

Answer:

A. V=2

Step-by-step:

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6x+3<7-2x<br> I’m not sure if I’m doing it right so an explanation would be nice

enot [183]

Answer:

x<0.5

Step-by-step explanation:

this is just like simplifiying equations if you've done that before

first you want to isolate the variable, so you want to combine the values of x (in this case it's 6x and the -2x)

so you can either add 2x to both sides or you can subtract 6x on both sides, in this case ill just add 2x to both sides.

Then you subtract 3 from both sides to get 8x<4

after you get that, you want to divide both sides by 8, and you generally want to do that step last, it makes it easier, and you get x<1/2 or 0.5

just a reminder that with working with inequalities, you want to remember to flip the direction the inequality is whenever you divide by a negative number

7 0

2 years ago

12/11k÷4/3k<br><br>simplify the fraction

Nonamiya [84]

Answer:

9/11

Step-by-step explanation:

12/11k÷4/3k

Copy dot flip

12/11k* 3k/4

36k / 44k

Divide the top and bottom by 4k

9/11

3 0

2 years ago

Read 2 more answers

Please show me how to solve the initial value problem <br> y'=tanx y(pi/4)=3

AlexFokin [52]

The ODE is separable, i.e. you can write

$\dfrac{\mathrm dy}{\mathrm dx}=\tan x\iff\mathrm dy=\tan x\,\mathrm dx$

Integrating both sides gives the general solution.

$\displaystyle\int\mathrm dy=\int\tan x\,\mathrm dx$
$y=-\ln|\cos x|+C$

Given that $y\left(\dfrac\pi4\right)=3$ , we have

$3=-\ln\left|\cos\dfrac\pi4\right|+C$
$3=-\ln\dfrac1{\sqrt2}+C$
$3-\ln\sqrt2=C$

and so the particular solution to the IVP is

$y=-\ln|\cos x|+3-\ln\sqrt2$
$y=3-\ln|\sqrt2\cos x|$