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katovenus [111]
3 years ago
15

The radius of the base of a cylinder is 39 in and its heigh is 33 in find the volume of the cylinder

Mathematics
1 answer:
Zina [86]3 years ago
6 0

Answer:

157,685.9601

Step-by-step explanation:

The area of the base can be found by

C=\pi r^2

The the volume can be measured by the area of the base multiplied by the height.

You might be interested in
What additional information do you need to prove triangle NOP = triangle QSR?
Wewaii [24]
After careful consideration i think I have an answer... 
So if you notice, These two triangles are a reflection of each other. 
Now even though these two triangles equal one another, we still have to consider the fact that they are different. (one side is the opposite of another)
So lets just name all the sides that equal each other. 
∠N = ∠Q
NO = QS
QR = NP
PO = SR
∠S = ∠O 
∠P = ∠R 

(by the way i'm going to be saying {the reflective side} every time i want to refer to the side with the two lines :P) - so bare with me. 

So therefore this would mean that ∠P = ∠S would be false, since one angle is from the side that is reflected and the other isn't. Makes sense?

So lets look over at the answers...

A.) PN = SQ 
For this answer choice, PN is on the non reflective side, while SQ is on the reflective side. Soooo... This answer choice is wrong. 

B.) NO = QR
NO  is part of the  unreflective side, while QR is part of the reflective side. 
Therefore this answer is wrong. They must be part of the same side. 

C.) ∠P = ∠S 
∠P is on the unreflective side, while angle ∠S is on the reflective side. 
There fore this answer is also wrong. 

D.) ∠O = ∠S 
Now ∠O is on the reflective side while ∠S is on the reflective as well. 
There fore this answer is correct . 

YOUR ANSWER IS. 
D.) ∠O = ∠S 

Good Luck! :)


6 0
3 years ago
Plz help me solve problems 9 and 10 thxxxxx I appreciate it
Olegator [25]
Question 9 answer is 0.375
Question 10 answer is 0.03125
8 0
3 years ago
Helpppppppppp<br> Urgenttttt<br> Pleaseeeee!
Alika [10]

Answer:

The first set is a set of linear equations.

The way to figure this out is pretty easy. If you want to see it visually, go search up desmos graphing calculator and put in these equations.

A linear equation is a function that has a constant slope, meaning that the rate it increases or decreases will never change. The first one is a set of linear equations because it is 2 equations with constant slopes, meaning that the slopes will never change no matter what y and x are.

The second set is not, because while the first equation is linear, the second is an inequality. While it is a straight line, it doesn't count as a linear equation.

The third set, both equations have exponents on the x, which means that the slope will change depending on x. This means that both of these are not linear equations.

The only set that is a linear set is the one that has only linear equations.

3 0
2 years ago
Can someone help me with this problem. I don’t know how to do volume.
densk [106]

Answer:

7.5in³

Step-by-step explanation:

1x5x1.5=7.5

7 0
3 years ago
Which of the following functions have a vertical asymptote for values of Ø such that cos Ø = 1?Select all that apply.
igomit [66]

Answer:

y=\cot \theta and y=\csc \theta

Step-by-step explanation:

Note that if \cos \theta=1, then \sin \theta=0.

Functions y=\cos \theta,\ \ y=\sin \theta do not have vertical asymptotes at all.

Vertical asymptotes have functions y=\tan \theta,\ \ y=\cot \theta,\ \ y=\sec \theta,\ \ y=\csc \theta.

Functions y=\tan \theta and y=\sec \theta have the same vertical asymptotes (when \cos \theta =0).

Functions y=\cot \theta and y=\csc \theta have the same vertical asymptotes (when \sin \theta =0). See attached diagram

3 0
3 years ago
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