Answer:
The lemonade costs 1.4.
Step-by-step explanation:
This question is solved using a system of equations.
I am going to say that:
x is the cost of a cookie.
y is the cost of a lemonade.
Total cost for cookie and lemonade is 1.80.
This means that 
.
As we want y, we have that 
Lemonade costs 1.00 more than the cookie?
This means that:
So
The lemonade costs 1.4.
Given that the debt has been represented by the function:
f(x)=-6x^2+8x+50
To get the number of years, x that it would take for the company to be debt free we proceed as follows:
we solve the equation for f(x)=0
hence:
0=-6x^2+8x+50
solving for x using the quadratic formula we get:
x=[-b+/-sqrt(b^2-4ac)]/2a
x=[-8+/-sqrt(8^2-4*(-6)*50)]/(-6*2)
x=[-8+/-√1264]/(-12)
x=27.552
x~28
Answer:
244 degrees
Step-by-step explanation:
Since one angle APE is 90 degrees, that means line segments AD and BE are perpendicular bisectors.
Since both segments go through the center, that means all the angles are central angles.
Since angle APE is 90 degrees, that also means that angle EPD is 90 degrees.
33k -9 = 90
33k = 99
k = 3
Since we know k we can substitute it to find angle CPD.
20 k + 4 = 20*3 + 4= 60+4= 64 degrees.
Central angles equal angles of arcs, so we can and angles APE, EPD, and DPC to find the measure of major arc CAD.
64+ 90 +90 = 244 degrees
So 5.10 is 100% and 0.57 is x%
percent means parts out of 100
5.10/100%=0.57/x% since they are equal (exg 2/4=3/6)
5.10/100=0.57/x
multipy both sides by x/0.57 to clear fraciton
(5.1x)/57=1
multiply both sides by 57 to get rid of the denomeator (bottom number
5.1x=57
divde both sides by 5.1
x=11.1765
increase of 11.2%
( an easy way is (0.57/5.1) times 100)
Answer:
P(A) = 0.2
P(B) = 0.25
P(A&B) = 0.05
P(A|B) = 0.2
P(A|B) = P(A) = 0.2
Step-by-step explanation:
P(A) is the probability that the selected student plays soccer.
Then:
P(B) is the probability that the selected student plays basketball.
Then:
P(A and B) is the probability that the selected student plays soccer and basketball:
P(A|B) is the probability that the student plays soccer given that he plays basketball. In this case, as it is given that he plays basketball only 10 out of 50 plays soccer:
P(A | B) is equal to P(A), because the proportion of students that play soccer is equal between the total group of students and within the group that plays basketball. We could assume that the probability of a student playing soccer is independent of the event that he plays basketball.
