Since Tina replaces the beads after each pick:
P(R,G,R)=(1/5)(1/5)(1/5)=1/125
The probability that he selected the special quarter is 87.5%.
<h3><u /></h3><h3><u>Probability</u></h3>
Given that Mandvil has one standard quarter and one special quarter with a Head on both sides, and he selects one of these two coins at random, and without looking at it first, he flips the coin three times, to determine, if he flips a Head three straight times, what is the probability that he selected the special quarter, the following calculation must be made:
- 1 - (standard quarter) = X
- 1 - (0.50^3) = X
- 1 - 0.125 = X
- 0.875 = X
- 0.875 x 100 = 87.5
Therefore, the probability that he selected the special quarter is 87.5%.
Learn more about probability in brainly.com/question/24217562
∠P = 6x + 6
∠Q = 2x + 11
∠R = 2x + 3
∠P + ∠Q + ∠R = 180
(6x + 6) + (2x + 11) + (2x + 3) = 180
10x + 20 = 180
10x = 160
x = 16
∠Q = 2x + 11 = 2(16) + 11 = 32 + 11 = 43
Answer: 43°
Answer:
y = -2x - 5
Step-by-step explanation:
The given slope, or m, is -2 and the given y-intercept, or b, is -5.
The y-intercept equation is y = mx + b, so by knowing this equation all you need to do is plug in the given slope and y-intercept
y = -2x - 5
