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prohojiy [21]
3 years ago
8

Write a decimal between 0.5 and 0.75

Mathematics
1 answer:
BabaBlast [244]3 years ago
4 0
Hello!  

Any decimal would be 0.51 all the way to 0.74.

Have a wonderful day!  :)

-L
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The price p (in dollars) and the quantity x sold of a certain product obey the demand equation:
katen-ka-za [31]
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What are the solutions of x^2-2x+5=0
sweet [91]

The solution of x^{2}-2 x+5=0 are 1 + 2i and 1 – 2i

<u>Solution:</u>

Given, equation is x^{2}-2 x+5=0

We have to find the roots of the given quadratic equation

Now, let us use the quadratic formula

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  --- (1)

<em><u>Let us determine the nature of roots:</u></em>

Here in x^{2}-2 x+5=0 a = 1 ; b = -2 ; c = 5

b^2 - 4ac = 2^2 - 4(1)(5) = 4 - 20 = -16

Since b^2 - 4ac < 0 , the roots obtained will be complex conjugates.

Now plug in values in eqn 1, we get,

x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4 \times 1 \times 5}}{2 \times 1}

On solving we get,

x=\frac{2 \pm \sqrt{4-20}}{2}

x=\frac{2 \pm \sqrt{-16}}{2}

x=\frac{2 \pm \sqrt{16} \times \sqrt{-1}}{2}

we know that square root of -1 is "i" which is a complex number

\begin{array}{l}{\mathrm{x}=\frac{2 \pm 4 i}{2}} \\\\ {\mathrm{x}=1 \pm 2 i}\end{array}

Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i

6 0
3 years ago
PLZ HELP,, WILL BE MUCH APPRECIATED!
docker41 [41]

Answer:

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Step-by-step explanation:

x=180

y=160

0.4(x+y)+42 =

0.4(180 + 160) +42 =

0.4(340)+42=

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3 years ago
Round 75.6475.6475, point, 64 to the nearest ten
Maru [420]

Answer: nearest tenth is 49.0

Step-by-step explanation:

Hope this helps!

7 0
3 years ago
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