3 years ago

Brianna rolls a number cube that has sides labeled 1 to 6 and flips a coin. Write the list of possible outcomes.

1 answer:

5 0

The sample space is {(1,H), (1,T), (2,H), (2,T), (3,H), (3,T), (4,H), (4,T), (5,H), (5,T), (6,H), (6,T)}

On the number cube, she could roll any of the numbers from 1 to 6. On the coin, she could flip heads or tails.

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Factorise this equation

pashok25 [27]

$x^{2} - 2x +35$

To factor we must first find factors of 35

The only factors of 35 are : 5 & 7

-2x is what 5 and 7 make

but only if 7 is negative and 5 is positive

so our final factors are

(x - 7) (x + 5)

______________________________________________

$2x^{2} +7x +6$

For the second equation, were going to multiple the coefficient of $x^{2}$ ( which is 2 ) by 6

We get 12

What factors of 12 add up to 7?

3 and 4

So our final factors are

(2x+3)(x+2)

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3 years ago

Round 1.24236 to the nearest hundredth

matrenka [14]

Answer:

1.24

Step-by-step explanation:

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3 years ago

Read 2 more answers

6) Convert 2pie/3 to degrees A) 30° B) 60° 120° D) 240°

Gennadij [26K]

It would be c . 1.20

4 0

2 years ago

Can anyone think of Think of a quadratic equation that has two (2) real number solutions? If you can, please write the equation

serious [3.7K]

$1( 1) {}^{2} + 1(1) - 2 = 0$

1(2)^2+3(2)-10 = 0

4 0

3 years ago

Factor 125x^3-1000. Show your work.

Salsk061 [2.6K]

The left term is (5x)³.

The right term is 10³.

So, you can use the formula for the factorization of the difference of cubes.

... a³ - b³ = (a-b)(a² +ab +b²)

Here, you have a=5x, b=10, so the factorization is

... 125x³ -1000 = (5x-10)(25x² +50x +100)

4 0

2 years ago