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Lera25 [3.4K]
4 years ago
15

Brianna rolls a number cube that has sides labeled 1 to 6 and flips a coin. Write the list of possible outcomes.

Mathematics
1 answer:
Gemiola [76]4 years ago
5 0
The sample space is {(1,H), (1,T), (2,H), (2,T), (3,H), (3,T), (4,H), (4,T), (5,H), (5,T), (6,H), (6,T)}

On the number cube, she could roll any of the numbers from 1 to 6.  On the coin, she could flip heads or tails.
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Mary has some trading cards. Julie has 3 times as many trading cards as Mary. They have 36 trading cards in all. Which of these
riadik2000 [5.3K]

Answer:

C. X+3x=36

Step-by-step explanation:

1. If you add the x's to get: 4x=36

2. Do division to get 9.

3. if you plug in 9 in the original,and multiply: 9+27=36

4. There's your answer..... and i ran out of steps.

3 0
3 years ago
A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he
Nina [5.8K]

The maximum units is 200 and , Total revenue is $8,000

<u>Step-by-step explanation:</u>

Here we have , A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he maximum reveremany should be manufactured to obtain this maximum units .Let's find out:

We have following function as R(x)=80x-0.2x^ 2 . Let's differentiate this and equate it to zero to find value of x for which the function is maximum!

⇒ R(x)=80x-0.2x^ 2

⇒ \frac{d(R(x))}{dx}=\frac{d(80x-0.2x^ 2)}{dx}

⇒ \frac{d(R(x))}{dx}=\frac{d(80x)}{dx}-\frac{d(0.2x^ 2)}{dx}}

⇒ 0=80-2x(0.2)

⇒ \frac{80}{0.4}=x

⇒ x=200

Now , Value of function at x=200 is :

⇒ R(200)=80(200)-0.2(200)^ 2

⇒ R(200)=16000-8000

⇒ R(200)=8000

Therefore , The maximum units is 200 and , Total revenue is $8,000

7 0
3 years ago
Rita is planting saplings along her garden fence. When she started, she had x packages of saplings with 5 saplings per package.
Arturiano [62]

Answer:

<u>A. When Rita started, she had 7 packages of saplings.</u>

<u>B. If we represent x (number of packages of saplings) on a number line graph, it will start on number 4 (number of packages Rita still has) then moves to the right to number 7, that is the number of packages when Rita started to plant.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Number of packages Rita started = x

Number of saplings per package = 5

Number of saplings planted by Rita = 15

Number of saplings left = 20

2. How many packages of saplings did she start with?

Number of packages Rita started = (Number of saplings planted by Rita + Number of saplings left)/Number of saplings per package

Replacing with the real values:

x = (15 + 20)/5

x = 35/5 = 7

<u>When Rita started, she had 7 packages of saplings.</u>

3. What would the solution look like on a number line graph?

If we represent x (number of packages of saplings) on a number line graph, it will start on number 4 (number of packages Rita still has) then moves to the right to number 7, that is the number of packages when Rita started to plant.

5 0
3 years ago
Is the expression X space logical or space (Y space logical and space Z )equivalent to (X space logical or space Y )space logica
Anit [1.1K]

Answer:

To prove:

X+Y.Z=(X+Y).(X+Z)

Taking R.H.S

= (X+Y).(X+Z)

By distributive law

= X.X+X.Z+X.Y+Y.Z --- (1)

From Boolean algebra

X.X = X

X.Y+X.Z = X.(Y+Z)

Using these in (1)

=X+X(Y+Z)+Y.Z

=X(1+(Y+Z)+Y.Z --- (2)

As we know (1+X) = 1

Then (2) becomes

=X.1+Y.Z

=X+Y.Z

Which is equal to R.H.S

Hence proved,

X+Y.Z=(X+Y).(X+Z)

8 0
3 years ago
A typical running track is an oval with 74-m-diameter half circles at each end. a runner going once around the track covers a di
denpristay [2]

Answer:

Her centripetal acceleration during the turn at each end of the track is 0.432\, \frac{m}{s^{2}}

Step-by-step explanation:

Total distance covered in one round , D= 400 m

Time taken to cover one round , T = 1 min 40 s = 100 sec

Speed of runner , V=\frac{D}{T}=\frac{400}{100}\, \frac{m}{s}= 4.0\, \frac{m}{s}

Now centripetal acceleration is given by

a_c=\frac{V^{2}}{R}

where V= 4.0\frac{m}{s}

Radius, R= \frac{Diameter}{2}=\frac{74}{2}m=37\, m

\therefore a_c=\frac{4^{2}}{37}\, \frac{m}{s^{2}}=0.432\, \frac{m}{s^{2}}

Thus her centripetal acceleration during the turn at each end of the track is 0.432\, \frac{m}{s^{2}}

4 0
4 years ago
Read 2 more answers
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