1. The linear equation:
y = m x + b
m = 3
- 2 = 3 · 1 + b
- 2 = 3 + b
b = - 5
Answer: A ) y = 3 x - 5
2. We will solve the system of equations:
12 = - 4 m + b / · ( - 1 )
23 = 7 m + b
----------------------
- 12 = 4 m - b
+
23 = 7 m + b
--------------------
11 = 11 m, m = 1, b = 16
Answer: A ) y = x + 16
See examples before for the method to solving literal equations for a given variable: Solve A = bh for b. Since h is multiplied times b, you must divide both sides by h in order to isolate b. Since (c+d) is divided by 2, you must first multiply both sides of the equation by 2.
An altitude is a line which passes through a vertex of a triangle, and is at right angles to the opposite side. A triangle has three altitudes.
What is asked here is that you isolate y so that the equation takes the form of y = ..., where ... will be something that contains a, b and c but not y. So how do we get there? By applying some standard permutations to equations like so:
aby - b = c
First, we bring the -b term to the right hand side by adding b left and right:
aby -b+b = c+b
The -b and +b cancel out, so we get:
aby = c + b
Then, we divide left and right hand side by ab:
aby/ab = (c+b)/ab
Again, the ab/ab on the left cancels out (it is 1), so we get:
y = (c+b)/ab
And we're done!
So you have to know that it is allowed to add or subtract something (anything) to/from the left and right hand side of an equation. Likewise, you have to know that it is allowed to multiply or divide by something, as long as it isn't 0.
250 you have to divide, btw im hella wrong
