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mamaluj [8]
4 years ago
12

Define an altitude of a triangle.

Mathematics
1 answer:
Setler79 [48]4 years ago
6 0
An altitude is a line which passes through a vertex of a triangle, and is at right angles to the opposite side. A triangle has three altitudes.
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URGENT HELP PLEASE: What are the values of a1 and r of the geometric series?
lawyer [7]

Answer:

Third option is the correct choice.

Step-by-step explanation:

a_1 is the first term of the sequence which is given to be 1.

r is the common ration which can be found as:

r=\frac{3}{1}=3\quad r=\frac{9}{3}=3

Best Regards!

6 0
3 years ago
How do I solve 4cos^2 x -1=0
tekilochka [14]
(cosx)^{2} = 1/4 <=> cosx = +1/2 or cosx = -1/2;
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5 0
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Read 2 more answers
A farmer wants to enclose a rectangular field that borders a river with 400 feet of fencing material. if the farmer does not fen
ICE Princess25 [194]
Let each side perpendicular to the river be "x".Then the side parallel to the river is "400-2x".
The formula for Area = width*length
A(x) = x(400-2x)
A(x) = 400x - 2x^2
You have a quadratic with a = -2 and b = 400
Maximum Area occurs where x = -b/2a = -400/(2*-2) = 100 ft. (width)
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3 0
3 years ago
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Art [367]
-3*-2*-2=6*-2=-12 because negative multiplied by negative is positive
8 0
4 years ago
How do you do these two questions?
Mice21 [21]

Answer:

a) d²y/dx² = ½ x + y − ½

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Step-by-step explanation:

a) Take the derivative with respect to x.

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d²y/dx² = ½ + (½ x + y − 1)

d²y/dx² = ½ x + y − ½

b) At (0, 1), the first and second derivatives are:

dy/dx = ½ (0) + (1) − 1

dy/dx = 0

d²y/dx² = ½ (0) + (1) − ½

d²y/dx² = ½

The first derivative is 0, and the second derivative is positive (concave up).  Therefore, the point is a relative minimum.

4 0
4 years ago
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