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vovangra [49]
3 years ago
15

a music streaming service charges a $20 membership fee each month. the streaming service charges $1.50 for every song that you d

ownload. how many songs did you download if you paid $45.50 in one month?
Mathematics
2 answers:
Anarel [89]3 years ago
3 0

Answer:

17

Step-by-step explanation:

If it costs $20 for the membership fee, then you can subtract that from the total monthly cost, giving you $25.50.

Then, you can divide this number by the price of each song to work out how many songs you downloaded, because you are simply rearranging the formula to work out the total price. $25.50 / $1.50 = 17.

viva [34]3 years ago
3 0

Answer:17

Step-by-step explanation:45.50 minus the monthly fee equal 25.50 ......then divide by 1.50

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 Because the pattern is a Geometric sequence.
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3 years ago
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1/3x−2= 3 What must the value of this number be?
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Answer: 15

Step-by-step explanation:

1/3x - 2 = 3

     1/3x = 5

          x = 15

6 0
3 years ago
At Dubai metro station, in a week 320 trains arrived. Out of these 5% arrived early and 15% arrived late. How many arrived on ti
dybincka [34]

<u><em>The </em></u><u><em>number of trains</em></u><u><em> that arrived Dubai metro station on time is; 272 trains. </em></u>

<u><em /></u>

  • We are told that 320 trains arrived the Dubai metro station in a week.

  • Now, we are told that 5% got there early and 15% got there late.

This means, the percentage that got there on time is;

100% - % of trains that got there late.

  • Therefore, percentage of trains that got there on time is;

100% - 15% = 85%

  • Since 85% of the trains got there on time, then number of trains that got there on time is;

85% × 320 = 272

  • Therefore, we can conclude that 272 trains arrived on time.

Read more at; brainly.in/question/33336249

4 0
2 years ago
Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)
DENIUS [597]

Compute the necessary values/derivatives of f(x) at x=1:

f(1)=3

f'(1)=2

f''(1)=-12

f'''(1)=-12

f^{(4)}(1)=48

f^{(5)}(1)=120

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) f(x) at x=1 by

T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5

T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5

###

Another way of doing this would be to solve for the coefficients a,b,c,d,e,g in

f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5

by expanding the right hand side and matching up terms with the same power of x.

5 0
3 years ago
On Monday, you realize that a significant theft occurred between 6PM Friday and 8AM Monday. You have good video tape of the time
Sergeu [11.5K]

For this one, find out how many hour have passed per day with 6 pm Friday being where you start.  

6 pm Friday- 6 pm Saturday =24

6 pm Saturday - 6 pm Sunday= 24

6 pm Sunday - 6 am Monday = 12 hours

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Now just add the amount of hours together

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Now convert that to minutes.

There are 60 minutes in 1 hour.  You multiply the amount of hours by 60 to get the minutes.

62 hours times 60 minutes in 1 hour

62*60= 3720.

So you will have a total of 3,720 minutes of tape to review.

8 0
3 years ago
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