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vovangra [49]
3 years ago
15

a music streaming service charges a $20 membership fee each month. the streaming service charges $1.50 for every song that you d

ownload. how many songs did you download if you paid $45.50 in one month?
Mathematics
2 answers:
Anarel [89]3 years ago
3 0

Answer:

17

Step-by-step explanation:

If it costs $20 for the membership fee, then you can subtract that from the total monthly cost, giving you $25.50.

Then, you can divide this number by the price of each song to work out how many songs you downloaded, because you are simply rearranging the formula to work out the total price. $25.50 / $1.50 = 17.

viva [34]3 years ago
3 0

Answer:17

Step-by-step explanation:45.50 minus the monthly fee equal 25.50 ......then divide by 1.50

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La potencia que se obtiene de elevar a un mismo exponente un numero racional y su opuesto es la misma verdadero o falso?
malfutka [58]

Answer:

Falso.

Step-by-step explanation:

Sea d = \frac{a}{b} un número racional, donde a, b \in \mathbb{R} y b \neq 0, su opuesto es un número real c = -\left(\frac{a}{b} \right). En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) <em>El exponente es cero.</em>

(b) <em>El exponente es un negativo impar.</em>

(c) <em>El exponente es un negativo par.</em>

(d) <em>El exponente es un positivo impar.</em>

(e) <em>El exponente es un positivo par.</em>

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, c = d = 1. La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

d' = d^{-n} y c' = c^{-n}

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

d' = \left(\frac{a}{b} \right)^{-n} y c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}

d' = \left(\frac{a}{b} \right)^{(-1)\cdot n} y c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}

d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}y c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}

d' = \left(\frac{b}{a} \right)^{n} y c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}

d' = \left(\frac{b}{a} \right)^{n} y c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}

d' = \left(\frac{b}{a} \right)^{n} y c' = \left[-\left(\frac{b}{a} \right)\right]^{n}

Si n es impar, entonces:

d' = \left(\frac{b}{a} \right)^{n} y c' = - \left(\frac{b}{a} \right)^{n}

Puesto que d' \neq c', la proposición es falsa.

(c) El exponente es un negativo par.

Si n es par, entonces:

d' = \left(\frac{b}{a} \right)^{n} y c' = \left(\frac{b}{a} \right)^{n}

Puesto que d' = c', la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

d' = d^{n} y c' = c^{n}

d' = \left(\frac{a}{b}\right)^{n} y c' = \left[-\left(\frac{a}{b} \right)\right]^{n}

d' = \left(\frac{a}{b} \right)^{n} y c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}

d' = \left(\frac{a}{b} \right)^{n} y c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}

Si n es impar, entonces:

d' = \left(\frac{a}{b} \right)^{n} y c' = - \left(\frac{a}{b} \right)^{n}

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

d' = \left(\frac{a}{b} \right)^{n} y c' = \left(\frac{a}{b} \right)^{n}

Si n es par, entonces d' = c' y la proposición es verdadera.

Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.

3 0
2 years ago
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