$\text{Let the number of dimes be x, then as per the friend the number of }\\
\text{quarters should be 8 more than dimes, so number of quarters}=x+8\\
\\
\text{we know that the value of 1 dime is }\$ 0.10 \text{ value of one quarter is }\$0.25\\
\\
\text{And since the total value of quarters and dimes is }\$2.80, \text{ so we have}\\
\\
0.10(x)+0.25(x+8)=2.80\\
\\
\Rightarrow 0.10x+0.25x+2=2.80\\
\\
\Rightarrow 0.35x=2.80-2\\
\\
\Rightarrow 0.35x=0.80$

$\Rightarrow x=\frac{0.80}{0.35}=2.29\\
\\
\text{so if we take 2 dimes then we'll have to take 10 quarters according to friend.}\\
\\
\text{So the statement of friend is }$ WRONG

6 0

3 years ago

Solve the Quadratic Equation . Show all of your work for full credit. 4x^2− 2x − 5= 0

max2010maxim [7]

Hope this helps! Don’t mind the part I crossed off.

8 0

3 years ago

Read 2 more answers