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inna [77]
3 years ago
7

The diameter of the base of a cylindrical can is 4 in. The height of the can is 6.5 in. Find the can’s surface area to the neare

st tenth.
Mathematics
2 answers:
kondaur [170]3 years ago
5 0
We know that

<span>diameter of the base of a cylindrical can= 4 in----------> r=2 in
h=6.5 in
</span>[surface area]=2*[pi*r²]+[2*pi*r*h]
then
[surface area]=2*[pi*2²]+[2*pi*2*6.5]=[ 25.13 ]+[ 81.68 ]=106.81 in²

the answer is 106.8 in²
garik1379 [7]3 years ago
5 0

Answer:

106.8 in2

Step-by-step explanation:

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3 years ago
The length of each side of a regular pentagon is increased by 8 inches, so the perimeter is now 65 inches. What is the original
evablogger [386]

<em>Here</em> as the <em>Pentagon</em> is <em>regular</em> so it's <em>all sides</em> will be of <em>equal length</em> . And if we assume It's each side be<em> </em><em><u>s</u></em> , then it's perimeter is going to be <em>(s+s+s+s+s) = </em><em><u>5s</u></em>.And as here , each <em>side</em> is increased by <em>8 inches</em> and then it's perimeter is <em>65 inches</em> , so we got that it's side after increament is<em> (s+8) inches</em> and original length is <em>s inches </em>. And if it's each side is <em>(s+8) inches</em> , so it's perimeter will be <em>5(s+8)</em> and as it's equal to <em>65 inches</em> . So , <em><u>5(s+8) = 65</u></em>

{:\implies \quad \sf 5(s+8)=65}

{:\implies \quad \sf 5s+5\times 8=65}

{:\implies \quad \sf 5s+40=65}

{:\implies \quad \sf 5s=65-40}

{:\implies \quad \sf 5s=25}

{:\implies \quad \sf s=\dfrac{25}{5}=5}

{:\implies \quad \bf \therefore \quad \underline{\underline{s=5\:\: Inches}}}

As we assumed the original side to be <em><u>s</u></em> .

<em>Hence, the original side's length 5 inches </em>

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2 years ago
Please help!
IgorC [24]

Answer:

(1,-4) is in quadrant IV.

Step-by-step explanation:

3 0
3 years ago
Hello, I really struggle with math and I was wondering if you could help me with the following problem please? It will be much a
xz_007 [3.2K]

Answer:

x=7

Step-by-step explanation:

Simplifying

3x + 2(4 + 6x) = 113

3x + (4 * 2 + 6x * 2) = 113

3x + (8 + 12x) = 113

Reorder the terms:

8 + 3x + 12x = 113

Combine like terms: 3x + 12x = 15x

8 + 15x = 113

Solving

8 + 15x = 113

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.

8 + -8 + 15x = 113 + -8

Combine like terms: 8 + -8 = 0

0 + 15x = 113 + -8

15x = 113 + -8

Combine like terms: 113 + -8 = 105

15x = 105

Divide each side by '15'.

x = 7

Simplifying

x = 7

5 0
2 years ago
Read 2 more answers
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