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3 years ago

Which graph represents the function f(x) =2|x|?

Mathematics

2 answers:

steposvetlana [31]3 years ago

6 0

Answer:

the third graph

love history [14]3 years ago

5 0

<h2>Answer:</h2>

The correct graph is Graph 3.

<h2>Step-by-step explanation:</h2>

We are given a modulus function f(x) by:

$f(x)=2|x|$

We will go through the following graphs by checking the value of the graph at some value of x and see whether the value on the graph at that x matches the value of f(x) at that particular x.

when x=1 we have:

$f(x)=2\times |1|\\\\f(x)=2$

Graph 1:

When x=1

we have:

$f(x)=0.5\neq 2$

Hence, Graph 1 does not represent the given function.

Graph 2:

when x=1 we have:

$f(x)=1\neq 2$

Hence, Graph 2 is not the answer.

Graph 4:

when x=1 we have:

$f(x)$

Hence, graph 4 is not the correct graph to represent f(x).

Hence, we are left with Graph 3.

When we plot the function f(x) we see that it matches the graph 3.

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Answer:

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Step-by-step explanation:

$MSE = \frac{sum (error)^{2} }{n-1} \\$

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Using the most recent value as the forecast for the next period, we have forecasts for the months as;

(1,-) , (2,25) , (3,13) , (4,21) , (5,13) , (6,20) , (7,22)

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Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

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$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

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