A) Using your equation from step 2d, estimate the GPA of a student who studies for 15 hours a

We want to construct a confidence interval at 99% of confidence, so then the significance level would be $1-0.99 =0.01$ and the value of $\alpha/2 =0.005$ . And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.

And if we find the critical value in the normal standard distribution or excel and we got:

$z_{\alpha/2}= \pm 2.576$

And we can use the following excel code:

"=NORM.INV(0.005,0,1)"

Step-by-step explanation:

For this case we have the following info given:

$\alpha=0.01, n =26, \sigma = 28.9$

We want to construct a confidence interval at 99% of confidence, so then the significance level would be $1-0.99 =0.01$ and the value of $\alpha/2 =0.005$ . And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.

And if we find the critical value in the normal standard distribution or excel and we got:

$z_{\alpha/2}= \pm 2.576$

And we can use the following excel code:

"=NORM.INV(0.005,0,1)"

7 0

3 years ago

How to solve 42j+18-19j=-28

Kryger [21]

Answer:

j=-2

Step-by-step explanation:

42j+18-19j=-28

Combine like terms

23j +18=-28

Subtract 18 from each side

23j +18-18 = -28 -18

23j =-46

Divide each side by 23

23j/23 = -46/23

j = -2

5 0

3 years ago

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The equation of the graphed line is x + 2y = 5. What is the x-intercept of the graph?

alexdok [17]

If you have to find x-intercept, then you have to equate y to 0. Thus,

when y=0, x+2·0=5 and x=5.

Point (5,0) is x-intercept.

Answer: (5,0)

6 0

3 years ago

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