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motikmotik
2 years ago
7

There are 16 students in a class with wooden pencils. There are 20 students in a class with mechanical pencils. If a school has

120 students with mechanical pencils, how many students would have wood pencils if the ratio of wooden pencils to mechanical pencils was the same throughout the school?
Mathematics
2 answers:
svet-max [94.6K]2 years ago
5 0

Answer:

maybe 100 cheak it please

IgorC [24]2 years ago
3 0

Answer:

100

Step-by-step explanation:

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Plsss Help me plsssssssssssss
Mazyrski [523]

Answer:

If, a = 2 and b = 3

<h3>Jada</h3><h3>10a + 1b = 7a + 5b  - 3a + 4b \\ 10(2) + 1(3) = 7(2) + 5(3) - 3(2) + 4(3) \\ 20 + 3 = 14 + 15 - 6 + 12 \\ 23 = 35 \\</h3>

It's not equivalent.

<h3>Diego</h3><h3>4a + 9b = 7a + 5b - 3a + 4b \\ 4(2) + 9(3) = 7(2) + 5(3) - 3(2) + 4(3) \\ 8 + 27 = 14 + 15 - 6 + 12 \\ 35 = 35 \\</h3>

It's equivalent.

The correct equation is 4a + 9b.

5 0
2 years ago
A farmer plants corn and wheat on a 180-acre farm. the farmer wants to plant three times as many acres of corn as wheat. write a
german

x=3y

x+y=180

The answer for this question

6 0
3 years ago
The sum of two numbers Is 55. The smaller number Is 5 less than the larger number. What are the numbers?​
Julli [10]

Answer:

the smaller is 25 and the bigger one is 30 .

Step-by-step explanation:

1.

x+y=55

y-5=x

------------

2.

x+y=55

y-x=5

2y = 60

y = 30

30 - 5 = 25

7 0
2 years ago
What is the geometric mean between 9/16 and 25/36
sergiy2304 [10]

Answer:

5/8

Step-by-step explanation:

Geometric mean is found by multiplying the n number of values and then taking the n-root.

To do this with these numbers, sqrt((9/16)*(25/36)) = (3/4)(5/6) = (1/4)(5/2)= 5/8

I hope this helps! :)

6 0
2 years ago
a fishbowl shaped like a sphere is filled with water. The fishbowl has a diameter of 16 inches. Which measurement is closest to
gregori [183]

Answer:

The volume of the water in the fishbowl is equal to

(682\frac{2}{3})\pi\ in^{3}  or  2,144.6\ in^{3}

Step-by-step explanation:

we know that

The volume of the sphere (a fishbowl) is equal to

V=\frac{4}{3}\pi r^{3}

In this problem we have

r=16/2=8\ in ----> the radius is half the diameter

substitute

V=\frac{4}{3}\pi (8^{3})=\frac{2,048}{3}\pi\ in^{3}

convert to mixed number

\frac{2,048}{3}\pi\ in^{3}=\pi (\frac{2,046}{3}+\frac{2}{3})=(682\frac{2}{3})\pi\ in^{3}

(3.14156)*(682\frac{2}{3})=2,144.6\ in^{3}

6 0
3 years ago
Read 2 more answers
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