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7nadin3 [17]
2 years ago
11

Write an equation that expresses the relationship between the side lengths of each triangle

Mathematics
1 answer:
skad [1K]2 years ago
3 0

Answer:

Step-by-step explanation:

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What is the area of the 3/4foot by 5/6 foot rectangle
marishachu [46]

Answer:

5/8 square feet

Step-by-step explanation:

\dfrac{3}{4}\cdot \dfrac{5}{6}=\dfrac{3\cdot 5}{4\cdot 6}=\dfrac{15}{24}=\dfrac{5}{8}. Hope this helps!

7 0
3 years ago
What is the sum 5/3 +(1/5) please and explain
solmaris [256]
We need to find a common denominator(bottom number of fraction)

5/3 = 25/15 (multiply both top and bottom by 5)
1/5 = 3/15 (multiply both top and bottom by 3)

Now since the denominator is the same we can add to get 25/15 + 3/15 = 28/15
7 0
4 years ago
Read 2 more answers
Solve the value for v.
NemiM [27]

Answer:

Hey mate !!

Your answer is so simple :)

<h2>V= 9°</h2>

Go through the explanation to understand.

Step-by-step explanation:

In the given question,

We see that 105° and it's adjacent angle (i.e. 8v+3° ) forms a supplementary angle. Which means the sum of 8v+3°+105° is 180°

<h3>Therefore,</h3>

According to the question

105 + 8v + 3 = 180

=  > 105 + 8v = 180 - 3

=  > 8v =  177 - 105

=  > 8v = 72

=  > v =  \frac{72}{8}

=  > v = 9

Answer the value of v is 9° .

Hope it helps you!!

#IndianMurga ツ

3 0
3 years ago
If the area of a square living room is 169 square feet . What is the perimeter of the room
stich3 [128]
The one wall would be 13 feet long.
13+13+13+13= 52 feet.
8 0
3 years ago
Read 2 more answers
The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms. Using the equation for R2, in terms of
ivanzaharov [21]
<h2>Answer:</h2>

R_2  is 3 ohms

<h2>Step-by-step explanation:</h2>

In a circuit containing two resistors R_1 and R_2 connected together in parallel, the total resistance R_T is given by;

\frac{1}{R_T} = \frac{1}{R_1}  + \frac{1}{R_2}              ---------(i)

<em>Make </em>R_2<em> subject of the formula;</em>

=> \frac{1}{R_2} = \frac{1}{R_T}  - \frac{1}{R_1}  

=> \frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}

=>   {R_2} = \frac{R_TR_1}{R_1 - R_T}       ---------------(ii)

From the question,

R_1 = 6Ω

R_T = 2Ω

Substitute these values into equation (ii) as follows;

=> {R_2} = \frac{2*6}{6 - 2}

{R_2} = \frac{12}{4}

R_2 = 3Ω

Therefore, the value of R_2 = 3 ohms or R_2 = 3Ω

3 0
3 years ago
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