The probability of obtaining two blue marbles without replacement is equal to 0.15.
We are given that:
The number of yellow marbles = 3
Number of red marbles = 9
Number of Blue marbles = 8
Total marbles = 3 + 9 + 8
Total marbles = 20
Now, we have to calculate the probability of obtaining two blue marbles without replacement.
The probability will be:
P( obtaining two blue marbles without replacement ) = 8 / 20 × 7 / 19
P( obtaining two blue marbles without replacement ) = 56 / 380
P( obtaining two blue marbles without replacement ) = 0.15
Therefore, the probability of obtaining two blue marbles without replacement is equal to 0.15.
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Answer:
Step-by-step explanation:
It's like solving any equation, except we have letters instead of numbers .
k = 3tm + rs {subtract rs from both sides}
k - rs = 3tm {divide both sides by (3m)}
{swap sides}
m≠0
{m must be ≠0 because you cannot divide by 0. There is no t for m=0}
7k/3 = 21
x 3 x3
7k = 63
/7 /7
k = 9
(7(9)/3 = 21 = 63/3 = 21 = 21 = 21)
Answer: x = -7
Step-by-step explanation:
2(6 + 3x) + 1 = - 5 + 3(x - 1)
(2) (6) + (2) (3x) + 1 = -5 + (3) (x) + (3) (-1)
12 + 6x + 1 = - 5 + 3x + - 1
( 6x ) + ( 12 - 1 ) = ( 3x ) + ( -5 + -3 )
6x + 13 = 3x - 8
6x + 13 - 3x = 3x - 8 - 3x
3x + 13 = -8
3x + 13 - 13 = -8 - 13
3x = -21
3x/3 -21/3
X = -7
(First one)Low - 18
Q1 - 20
Median - 25
Q3 - 30
(Last one) High - 34
