Question

Write an equation in slope-intercept form for the line that passes through (6, 6) and is perpendicular to -x+3y= -6

Answer 1

Answer:

y= -3x+24

Step-by-step explanation:

First find the slope of the line

-x + 3y = -6

Add x to each side

3y = x-6

Divide by 3

3y/3 = 1/3 x -6/3

y = 1/3x -2

The slope is 1/3 since it is in the form y = mx+b where m is the slope

Perpendicular lines have slopes that multiply to -1

1/3 * m = -1

m = -1 * 3/1

m = -3

The slope of the perpendicular line is -3

Slope intercept form is

y = mx+b where m is the slope and b is the y interceot

y = -3x+b

We have a point ( 6,6)

6 = -3(6) +b

6 = -18+b

Add 18 to each side

6+18 = -18+b+18

24 = b

y= -3x+24

Answer 2

Answer:

y= -3x+24

Step-by-step explanation:

hope this helps!