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3 years ago

Another plsssss answer the answer choices are 1 2 3 4

Mathematics

2 answers:

denis-greek [22]3 years ago

5 0

Answer:

I think it's 1 sorry if it is wrong i wish is right.

Step-by-step explanation:

marissa [1.9K]3 years ago

3 0

Answer:

Explanation:

A translation is when a shape is moved to a different location, and three is the only one that isn't flipped in some way.

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RSM PROBLEM NEED HELP!!!!!! In the figure, if PN = LN, NP ∥MQ, and QL

meriva

The value of x is 67°

<u>Step-by-step explanation:</u>

Given that

PN=LN

NP||MQ

QL bisects <PQM

therefore <PQL=<LQM

NP||MQ and NM is a transversal

<PNL+<LMQ=180°(angles on the same side of the transversal are supplementary)

<PNL+54=180°

<PNL=180-54=126°

Consider ΔPNL

since PN=NL,the triangle is isocelus

<NPL=<NLP=a

<NPL+<NLP+<PNL=180°

a+a+126=180°

2a+126=180

2a=180-126

=54°

a=54/2=27°

consider the point L

<NLP+<PLQ+<MLQ=180°

27+70+<MLQ=180

<MLQ=180-97=83°

consider ΔLQM

<LQM+<LMQ+LMQ=180

<LQM+83+54=180

<LQM=180-(83+54)=180-137=43°

<PQL=43°(since<PQL=<LQM)

considerΔPQL

x+70+<PQL=180°

x+70+43=180°

x+113=180

x=180-113

=67°

The value of x is 67°

7 0

4 years ago

Rearranging formula

allochka39001 [22]

Answer:

Arlo's weight = 52.3 kg

Explanation:

Let Arlo be "x"

Then,

Arlo = x

Bert = x+20 (Because Bert is 20 heavier than Arlo)

Cassie = x+20-5 (Because Cassie is 5 lighter than Bert)

Donnie = $\frac{x+20}{2}$ (Because Donnie is half of Bert's weight)

Average = 57

Step by step Calculations:

57 = $\frac{(x) + (x+20) + (x+20-5) + (\frac{x+20}{2} )}{4}$ (The whole divided by 4 because the total people is 4)

57*4 = x + x + 20 + x + 20 - 5 + $\frac{x+20}{2}$

228 = 3x + 35 + $\frac{x+20}{2}$

228 - 3x - 35 = $\frac{x+20}{2}$

193 -3x = $\frac{x+20}{2}$

2(193 - 3x) = x + 20

386 - 6x = x + 20

386 - 20 = x + 6x

366 = 7x

x = $\frac{366}{7}$

x = 52.3 kg (corrected to 3 significant figures)

Therefore Arlo's weight is 52.3 kg

8 0

3 years ago

Help me please ill mark brainliest please be correct

Vedmedyk [2.9K]

The answer to this is 5

8 0

3 years ago

15) My bag contains two books each of weight kg and 3/7 folders each of weight

8_murik_8 [283]

Answer:

Step-by-step explanation:

221

3 0

3 years ago

Read 2 more answers

The population of a town doubled approximately every 5 years during the first several decades after it was founded. If the origi

zzz [600]

Answer:

624 people

(I put two ways to look at the problem.)

Step-by-step explanation:

What is describe here is an exponential function of the form:

$P=P_0 e^{kt}$

$t$ is the number of years after 1761.

$P_0$ is the initial population.

So t=0 represents year 1761.

t=1 represents year 1762

t=2 represents year 1763

....

t=20 represents year 1781.

So we have the doubling time is 5 years. This means the population will be twice what it was in 5 years. Let's plug this into:

$P=P_0e^{kt}$

$2P_0=P_0e^{k\cdot 5}$

Divide both sides by $P_0$ :

$2=e^{5k}$

Convert to logarithm form:

$5k=\ln(2)$

Multiply both sides by 1/5:

$k=\frac{1}{5}\ln(2)$

$k=\ln(2^{\frac{1}{5}})$ By power rule.

So in the next sentence they actually give us the initial population and we just found k so this is our function for P:

$P=39e^{\ln(2^{\frac{1}{5}})t}$

So now we plug in 20 to find how many residents there were in 1761:

$P=39e^{\ln(2^{\frac{1}{5}})(20)}$

This is surely going to the calculator:

$P=624$

Now if you don't like that, let's try this:

Year 0 we have 39 people.

Year 5 we have 39(2)=78 people.

Year 10 we have 78(2)=156 people.

Year 15 we have 156(2)=312 people.

Year 20 we have 312(2)=624 people.

7 0

3 years ago