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Oksi-84 [34.3K]
2 years ago
13

Solve...............

Mathematics
1 answer:
Vladimir [108]2 years ago
7 0

Answer:

To graph an inequality, treat the <, ≤, >, or ≥ sign as an = sign, and graph the equation. ... If the inequality is ≤ or ≥, graph the equation as a solid line. This line divides the xy- plane into two regions: a region that satisfies the inequality, and a region that does not. Next, pick a point not on the line.

Step-by-step explanation:

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  • <em>Refer to attached.</em>

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Solve this x²+8/10 -x = 10/2
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x^2+\frac{8}{10}-x=\frac{10}{2}\\&#10;x^2-x+\frac{8}{10}-\frac{10}{2}=0\\&#10;x^2-x+\frac{8}{10}-\frac{50}{10}=0\\&#10;x^2-x-\frac{42}{10}=0\\&#10;x^2-x+\frac{1}{4}-\frac{1}{4}-\frac{42}{10}=0\\&#10;(x-\frac{1}{2})^2=\frac{1}{4}+\frac{42}{10}\\&#10;(x-\frac{1}{2})^2=\frac{5}{20}+\frac{84}{20}\\&#10;(x-\frac{1}{2})^2=\frac{89}{20}\\&#10;x-\frac{1}{2}=\sqrt{\frac{89}{20}} \vee x-\frac{1}{2}=-\sqrt{\frac{89}{20}}\\&#10;x=\frac{1}{2}+\frac{\sqrt{89}}{\sqrt{20}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{\sqrt{20}}\\&#10;&#10;&#10;
x=\frac{1}{2}+\frac{\sqrt{89}}{2\sqrt{5}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{2\sqrt5}}\\&#10;x=\frac{1}{2}+\frac{\sqrt{445}}{10} \vee x=\frac{1}{2}-\frac{\sqrt{445}}{10}}\\&#10;x=\frac{5+\sqrt{445}}{10} \vee x=\frac{5-\sqrt{445}}{10}}\\
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