The <em>vertex</em> form of the <em>quadratic</em> equation, written in <em>standard</em> form, f(x) = 2 · x² - 20 · x + 8 is f(x) + 75 = 2 · (x - 5)².
<h3>What is the vertex form of a quadratic equation?</h3>
In this problem we have a <em>quadratic</em> equation in <em>standard</em> form, whose form is defined by f(x) = a · x² + b · x + c, where a, b, c are <em>real</em> coefficients, and we need to transform it into <em>vertex</em> form, defined as:
f(x) - k = C · (x - h)² (1)
Where:
- (h, k) - Vertex coordinates
- C - Vertex constant
This latter form can be found by algebraic handling. If we know that f(x) = 2 · x² - 20 · x + 8, then its vertex form is:
f(x) = 2 · x² - 20 · x + 8
f(x) = 2 · (x² - 10 · x + 4)
f(x) + 2 · 25 = 2 · (x² - 10 · x + 25)
f(x) + 75 = 2 · (x - 5)²
The <em>vertex</em> form of the <em>quadratic</em> equation, written in <em>standard</em> form, f(x) = 2 · x² - 20 · x + 8 is f(x) + 75 = 2 · (x - 5)².
To learn more on quadratic equations: brainly.com/question/1863222
#SPJ1
1.15/3 = 20 minutes worth = 0.383
60 minutes+20 minutes=80 minutes = 1.15+0.383=1.53
1.5/3 = 0.5 = 20 minutes
60 minutes+20 minutes=80 minutes =1.5+0.5=2
2-1.53=0.47 therefore it is 0.47 minutes quicker with Model A
<span>f(x)=2x
f(1)=2*1=2
f^2(1)=2*2*1=4
f^3(1) =2*2*2*1=8
1. If you
continue this pattern, what do you expect would happen to the numbers as
the number of iterations grows?
I expect the numbers continue growing multiplying each time by 2.
Check your result by conducting at
least 10 iterations.
f^4(1) = f^3(1) * f(1) = 8*2 = 16
f^(5)(1) = f^4(1) * f(1) = 16 * 2 = 32
f^6 (1) = f^5 (1) * f(1) = 32 * 2 = 64
f^7 (1) = f^6 (1) * f(1) = 64 * 2 = 128
f^8 (1) = f^7 (1) * f(1) = 128 * 2 = 256
f^9 (1) = f^8 (1) * f(1) = 256 * 2 = 512
f^10 (1) = f^9 (1) * f(1) = 512 * 2 = 1024
2. Repeat the process with an initial value of −1.
What happens as the number of iterations grows?
f(-1) = 2(-1) = - 2
f^2 (-1) = f(-1) * f(-1) = - 2 * - 2 = 4
f^3 (-1) = f^2 (-1) * f(-1) = 4 * (-2) = - 8
f^4 (-1) = f^3 (-1) * f(-1) = - 8 * (-2) = 16
f^5 (-1) = f^4 (-1) * f(-1) = 16 * (-2) = - 32
As you see the magnitude of the number increases, being multiplied by 2 each time, and the sign is aleternated, negative positive negative positive ...
</span>
112000 because the thousands is where the two is placed
