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adoni [48]
3 years ago
7

Write the following set in roster form and in set-builder notation.

Mathematics
1 answer:
expeople1 [14]3 years ago
7 0
Assuming that by greater you mean strictly greater :

Roster form : P=(-1,0,1,2)

Set builder notation : P=\{z\in\Bbb{Z}\mid-2
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PLEASE HELP FOR 30 POINTS....GEOMETRY/TRIG
Advocard [28]

Answer:

10/cot 62 degrees

Step-by-step explanation:

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3 years ago
Suppose you have a bag containing 2 black marbles and 3 red marbles. You reach into the bag, select a marble, see what color it
TiliK225 [7]

Answer:

\dfrac{9}{25}

Step-by-step explanation:

Given that the bag contains black and red marbles.

Number of black marbles in the bag = 2

Number of red marbles in the bag = 3

Total number of marbles in the bag = Number of black marbles + Number of red marbles = 2 + 3 = 5

Let us have a look at the formula for probability of an event E, which can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(\text{First red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5 }

Now, the marble chosen at first is replaced.

Therefore, the count remains the same.

P(\text{Second red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5}

Now, the <em>required probability</em> can be found as:

P(\text{First red marble})\times P(\text{Second red marble}) = \dfrac{3}{5}\times \dfrac{3}{5} = \bold{\dfrac{9}{25} }

3 0
3 years ago
1. D=5.9 ft.
Shtirlitz [24]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Here's the solution ~

As we know, we can calculate the circumference of a circle in terms of its diameter as :

\qquad \sf  \dashrightarrow \:c =  \pi d

where, c = circumference and d = diameter

And also, circumference of circle is terms of radius (r) is :

\qquad \sf  \dashrightarrow \:c =  2\pi r

Now, let's move on to questions ~

<h3>First </h3>

\qquad \sf  \dashrightarrow \:3.14 \times 5.9

\qquad \sf  \dashrightarrow \: \approx18.53 \: ft

<h3 />

・ .━━━━━━━†━━━━━━━━━.・

<h3>Second</h3><h3 /><h3 /><h3 /><h3>\qquad \sf  \dashrightarrow \:3.14 \times 3.2</h3>

\qquad \sf  \dashrightarrow \: \approx10.048 \: ft

・ .━━━━━━━†━━━━━━━━━.・

<h3>Third</h3>

\qquad \sf  \dashrightarrow \:3.14 \times 6.1

\qquad \sf  \dashrightarrow \: \approx19.15 \: ft

・ .━━━━━━━†━━━━━━━━━.・

<h3>Fourth</h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  3.7

\qquad \sf  \dashrightarrow \: \approx2×11.62  \: m

\qquad \sf  \dashrightarrow \: \approx23.24  \: m

・ .━━━━━━━†━━━━━━━━━.・

<h3>Fifth </h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  6.2

\qquad \sf  \dashrightarrow \: \approx2× 19.47 \: units

\qquad \sf  \dashrightarrow \: \approx38.94  \: m

・ .━━━━━━━†━━━━━━━━━.・

<h3>Sixth</h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  5.1

\qquad \sf  \dashrightarrow \: \approx2×16.01 \: ft

\qquad \sf  \dashrightarrow \: \approx \: 32.02m

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

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