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Semmy [17]
2 years ago
13

The book Kathy is reading is 540 pages long. So far, she has read 405 pages. What percent of the book does she have left to read

?
A. 20%
B. 25%
C. 75%
D. 80%
Mathematics
2 answers:
Elan Coil [88]2 years ago
8 0
405/540 = 0.75 —> 75%

The answer is C.
hichkok12 [17]2 years ago
5 0

Answer:

B. 25%

Step-by-step explanation:

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The sum of twice a number and four times the number is 54. Find the number.
miv72 [106K]
Twice a number can be written as 2n.

Four times the number can be written as 4n.

If the sum of 2n and 4n equals 54, then:

6n = 54

Divide both sides by 6 to solve for n:

n = 9
5 0
2 years ago
Read 2 more answers
F(x) = -2x − 5 for x = 3
patriot [66]
X=-2x-5 x=3
x=-2(3)-5
x=-6-5
x= -11
4 0
3 years ago
I WILL MARK YOU AS BRAINLIEST
Anna007 [38]

Answer:

95 or more

Step-by-step explanation:

an average of 89 gives you a mean score of 445 to get an average of 90 he needs a 540 in total for all 6 exams that is a 95 or better.

3 0
3 years ago
At a local dealership 30% of cars are SUVs, 50% of the cars are painted white, and 15% are white and an SUV. If we randomly sele
alex41 [277]

Answer:

1/8, 0.0625 , or 6.25%

Step-by-step explanation:

50% of the cars are painted white.

1/2 * 1/2 = 1/4 * 1/4 = 1/8

Probability of A occuring 4 time(s) = 0.54 = 0.0625

Probability of A NOT occuring = (1 - 0.5)4 = 0.0625

Probability of A occuring = 1 - (1 - 0.5)4 = 0.9375

6 0
3 years ago
A car radiator needs a 80% antifreeze solution. The radiator now holds 15 liters of a 70% solutions. How many liters of this sho
slavikrds [6]
So... the radiator has 15 liters of 70% antifreeze.. but needs an 80% antifreeze

well, so, you need to drain some and put some with higher percentage, seems to be, you will end up at the same 15 liters, possible the radiator's capacity, of 80% antifreeze

so, the same amount going out, of 70% is the same amount going in, of 100% antifreeze

now.. let's use the decimal format for the percents, or 70% is 70/100 or 0.7 and so on
\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentration\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{70\% sol'n, out}&x&0.7&0.7x\\
\textit{100\% sol'n, in}&x&1.00&x\\
\textit{current 70\% sol'n}&15&0.7&10.5\\
-----&-----&-------&-------\\
mixture&15&0.8&12
\end{array}

so.. let's subtract, from the current solution, 0.7x and add 1x or x, our antifreeze concentration amount, should be 12 though

10.5 - 0.7x + x = 12

solve for "x"

3 0
3 years ago
Read 2 more answers
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