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Zepler [3.9K]
3 years ago
10

How to do questions C and E ? Please help !!! Thank You :)

Mathematics
1 answer:
mestny [16]3 years ago
6 0
It is the right answer.
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What is function and how is it related to domain and range?​
const2013 [10]

Answer:

Function- a relationship or expression involving one or more variables.

A domain refers to the set of possible input values.

The range is the set of possible output values.

Step-by-step explanation:

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3 years ago
Describe the results of a similarity transformation
chubhunter [2.5K]

Answer:

frist it goes by a train


Step-by-step explanation:

2=2=2=444=11111111

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3 years ago
How do you wright twelve and a half trillion in scientific notation?
leva [86]
<span>twelve and a half trillion = 12.5 x 10^12
1.25 x 10^13 </span><span>in scientific notation</span>
3 0
3 years ago
Read 2 more answers
An international polling agency estimates that 36 percent of adults from Country X were first married between the ages of 18 and
alukav5142 [94]

Answer:

(B) 0.2843

Step-by-step explanation:

Let d be the difference in proportions from Country X and Country Y who were first married between the ages of 18 and 32.

Then hypotheses are

H_{0}: d=0.15

H_{a}: d<0.15

Test statistic can be found using the equation

z=\frac{p1-p2-0.15}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of Country X (0.36)
  • p2 is the sample proportion of Country Y (0.26)
  • p is the pool proportion of p1 and p2 (\frac{60*0.36+50*0.26}{50+60}=0.31)
  • n1 is the sample size of adults from Country X (60)
  • n2 is the sample size of adults from Country Y (50)

Then z=\frac{0.36-0.26-0.15}{\sqrt{{0.31*0.69*(\frac{1}{60} +\frac{1}{50}) }}} ≈ 0.5646

p-value of test statistic is ≈ 0.2843

p-value states the probability that the difference in proportions between a random sample of 60 adults from Country X and a random sample of 50 adults from Country Y who were first married between the ages of 18 and 32 is at least 0.15

3 0
3 years ago
The completely factored form of 2d^4 + 6d^3 - 18d^2 - 54d is
Pachacha [2.7K]
The first step we take is to factor out a GCF:

2d(d³ + 3d² - 9d - 27)

Now, we can factor what's in the parenthesis by grouping (don't forget to keep the 2d we factored out):

2d[d²(d+3) -9(d+3)]
2d(d²-9)(d+3)

d²-9 can still be factored because it is the difference of two squares:

2d(d+9)(d-9)(d+3)

That is the completely factored form.
3 0
3 years ago
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