Work done on cart
:
W
=
6000
J
Kinetic energy of cart
:
E
K
=
6000
J
Explanation:
Work done
W
is defined as the product of force
F
and distance
s
:
⇒
W
=
F
⋅
s
Let's substitute the values of
F
and
s
into the equation:
⇒
W
=
300
N
⋅
20
m
⇒
W
=
300
kg
⋅
m s
−
2
⋅
20
m
⇒
W
=
300
⋅
20
kg
⋅
m
2
s
−
2
⇒
W
=
6000
kg
⋅
m
2
s
−
2
∴
W
=
6000
J
The gain in kinetic energy
E
K
is the same amount as the work done moving the cart:
∴
E
K
=
6000
A is aldult tickets
b is child tickets
b = 2/3 a
7a + 12b = 90
7a + 12 x 2/3 a = 90
7a + 8a = 90
15a = 90
a = 6; b = 4
We know, Circumference = <span>π * Diameter
So, c = </span><span>π * 8
c = 8</span><span>π
In short, Your Answer would be Option C
Hope this helps!</span>
Answer:
-4x^2+5x-28
Step-by-step explanation:
Expand -7(x^2 +4) = 3x^2+5x-7x^2-28
Simplify 3x^2+5x-7x^2-28 = -4x^2+5x-28
