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3 years ago

Yo can someone help me out

Mathematics

2 answers:

FromTheMoon [43]3 years ago

8 0

Answer:

Step-by-step explanation:

The amount of tickets p is more or equal to 18

LekaFEV [45]3 years ago

6 0

Answer: d

Step-by-step explanation:

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The median of 1,2,2,8,9,14

Hatshy [7]

Answer:

Step-by-step explanation:

Median is the middle number

Can I get brainliest

7 0

3 years ago

Read 2 more answers

The system x−6y=4, 3x−18y=4 has no solution.

stealth61 [152]

Ok fist you wanna change your question into a equation so it would turn into x-6 y=4 and 4.3x - 18 y = 4 then multiple both sides and that pups give you 43x - 180 y = 40 and eliminate one variable and I don’t wanna keep explaining but the the answer is

ANSWER: (x , y ) = (- 80 over 13, and - 22 over 13

6 0

3 years ago

Javier used the equivalent ratios to find the number of millimeters in 8 inches. StartFraction 8 inches Over question mark milli

joja [24]

Answer:

203.20 millimeters

Step-by-step explanation:

StartFraction 8 inches Over question mark millimeters EndFraction = StartFraction 40 inches Over 1,016 millimeters

8 inches / ? Millimeters = 40 inches / 1,016 millimeters

8 × 1,016 = ? × 40

8,128 = 40?

Divide both sides by 40

? = 8,128 / 40

= 203.20

? = 203.20 millimeters

There are 203.20 millimeters in 8 inches

7 0

3 years ago

Read 2 more answers

Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

3 0

3 years ago

Answer both parts a and b for full credit.

Maslowich

Answer:

A) The store charges $94.50 for the skis!

B) The final price is 150% of the original price!

Step-by-step explanation:

A) 63 x (1 + 0.50) = 94.5

B) 94.50 = P(63)

94.50 (1/63)=P(63)(1/63)

1.50

6 0

3 years ago