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3 years ago

Which equation requires the multiplication property of equality to be solved?

Mathematics

2 answers:

prohojiy [21]3 years ago

4 0

Answer:

201.6 = 11.2f

Step-by-step explanation:

tangare [24]3 years ago

4 0

201.6 = 11.2f Ik someone answered but I wanted to say it’s correct

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HELP PLEASE 20 points

Troyanec [42]

Go and download Photomath and it will scan the problem for you and tell you the answer with the graph

8 0

3 years ago

Show how you can use the distributive property to rewrite and find (32x6)+(32x4)

Nikitich [7]

32(6+4) =320 you need to find the common term and then place on ouside of the parentheses

8 0

3 years ago

Read 2 more answers

Pls answer thank you

Rashid [163]

Answer:

<h2>ANSWER </h2>

 

 $as \: the \: diagram \: given \: \\ surface \: area \: = (9 \times 17 \times 2 + 4 \times 17 + 4 \times 9 + 4 \times 17 + 9 \times 4) {in}^{2}$ 

 $(153 \times 2+ 68 + 36 + 68 + 36 \\ 306 + 104 + 104 ) {in}^{2}$ 

 $544 \:{ in}^{2}$ 

So the answer here = 544 in^2

4 0

3 years ago

What are the first five common multiples of 4 and 7

denis23 [38]

Easy, just write out the multiple of the numbers.

4: 4,8,12,16,20,24,28,32,36,40,44,48,52,56,60

7: 7,14,21,28,35,42,49,56,63,70

Etc.

But a few common multiples:

28,56,84,112,140

These are the first 5 common multiples of 4 and 7.

6 0

4 years ago

A random sample of 102 full-grown lobsters had a mean weight of 16 ounces and a standard deviation of 3.4 ounces. Construct a 98

pshichka [43]

Answer:

The best point estimate for a confidence interval estimating the population μ is 16 ounces.

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The best point estimate for a confidence interval estimating the population μ is

The sample mean, so 16 ounces.

T interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 102 - 1 = 101

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 101 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.98}{2} = 0.99$ . So we have T = 2.36

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.36\frac{3.4}{\sqrt{102}} = 0.79$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 16 - 0.79 = 15.21 ounces

The upper end of the interval is the sample mean added to M. So it is 16 + 0.79 = 16.79 ounces

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

4 0

3 years ago