All categories

4 years ago

A triangular pyramid is cut by a plane in which case is the cross section a quadrilateral

Mathematics

1 answer:

ikadub [295]4 years ago

5 0

Answer:

when the plane intersects the base and all three lateral faces of the pyramid

Step-by-step explanation:

When a plane intersects a plane, it forms a line.

A triangular pyramid has four faces.

To form four straight lines and therefore a quadrilateral, the intersecting plane must intersect all four faces.

You might be interested in

The ratio of men to women in a certain factory is 3 to 4. There are 222 men. How many workers are there?

IgorLugansk [536]

The ratio of men to women in a certain factory = 3:4
The total number of men in the factory = 222
Let us assume the common ratio to be = x
Then
3x = 222
x = 222/3
= 74
Then
The total number of women workers in the factory = 4 * 74
= 296
So
The total number of workers in the factory = 296 + 222
= 518
From the above deduction we can easily conclude that there are a total of 518 workers in the factory.

8 0

3 years ago

2637.50 divided by 350

gulaghasi [49]

The answer to 2637.50 divided by 350 is <span>7.53571428571</span>

3 0

4 years ago

Read 2 more answers

How to Distribute 3(2-3x)

Aleksandr [31]

Answer:

6 -9x

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

bro I promise if someone reports this for no reason or send a malware link that i can scan ima hack u

ratelena [41]

Answer:

"hack you" lol answer is 22in

Step-by-step explanation:

the base of the pyramid is 100in^2

so the rest of the surface area is 440

formula for a triangle area is A=1/2bh

1 of the triangles is 110 440/4

110=1/2*10*h

110=5*h

h=22

6 0

3 years ago

xz_007 [3.2K]

Answer:

$Center = \boxed{1}, \: \boxed{ - 2} \: ; \: Radius = \boxed{3}$

Step-by-step explanation:

${x}^{2} + {y}^{2} - 2x + 4y - 4 = 0 \\ \\ ({x}^{2} - 2x + 1 - 1) + ( {y}^{2} + 4y + 4 - 4) - 4 = 0 \\ \\ ( {x}^{2} - 2x + 1) + ( {y}^{2} + 4y + 4) - 9 = 0 \\ \\ {(x - 1)}^{2} + {(y + 2)}^{2} = 9 \\ \\ {(x - 1)}^{2} + {(y + 2)}^{2} = {3}^{2} \\ \\ equating \: it \: with \\ \\ {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} \\ \\ h = 1 \\ k = - 2 \\ r = 3 \\ \\ center = \boxed{1} \: \boxed{ - 2} \: \: radius = \boxed{3}$

3 0

3 years ago