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Goshia [24]
2 years ago
14

5) The solution to 7X2 + 2X – 1 = 0 can be written as:

Mathematics
2 answers:
belka [17]2 years ago
5 0

Answer:

Step-by-step explanation:

7x² + 2x - 1 = 0

x = (-2 ±\sqrt{2^2 - 4(7)(-1)} )/ (2(7))

x = (-2 ± \sqrt{32} ) /14

x = (-2 ± 4\sqrt{2} ) /14

x = \frac{-1}{7} ± \frac{2}{7}\sqrt{2}

tia_tia [17]2 years ago
4 0

Answer:

2/7 or -30/7

Step-by-step explanation:

Use the quadratic formula

a = 7, b = 2, c = -1

-2 + or - (sqrt (2^2 - 4 * 7 * -1) / 2 * 7

-2 + or - 32/14

-2 + or -  16/7

2/7, or -30/7

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The sum of two numbers is 70 and their difference is 30. Find the two numbers
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Difference means subtract each other

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Read 2 more answers
Please help, I need input on if I did this correctly and you just substitute.
kow [346]

The value of h(t) when t=\frac{15}{32} is 10.02.

Solution:

Given function h(t)=-16t^2+15t+6.5

To find the value of h(t) when t=\frac{15}{32}:

h(t)=-16t^2+15t+6.5

Substitute t=\frac{15}{32} in the given function.

$h\left(\frac{15}{32} \right)=-16\left(\frac{15}{32} \right)^2+15\left(\frac{15}{32} \right)+6.5

            $=-16\left(\frac{225}{1024} \right)+15\left(\frac{15}{32} \right)+6.5

Now multiply the common terms into inside the bracket.

           $=-\left(\frac{3600}{1024} \right)+\left(\frac{225}{32} \right)+6.5

Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.

          $=-\left(\frac{225}{64} \right)+\left(\frac{225}{32} \right)+6.5

To make the denominator same, take LCM of the denominators.

LCM of 64 and 32 = 64

        $=-\left(\frac{225}{64} \right)+\left(\frac{225\times2}{32\times2} \right)+6.5\times\frac{64}{64}

        $=-\frac{225}{64} +\frac{450}{64}+\frac{416}{64}

        $=\frac{-225+450+416}{64}

       $=\frac{641}{64}

       = 10.02

$h\left(\frac{15}{32} \right)=10.02

Hence the value of h(t) when t=\frac{15}{32} is 10.02.

8 0
3 years ago
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