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xxTIMURxx [149]
3 years ago
5

Solve | x | < 10

Mathematics
1 answer:
Neko [114]3 years ago
8 0

Answer:

Right answer is B) x>-10 and x<10

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Perimeter of a rectangle is 52 feet. If the length is 10 less than 2 times the width, what is the width?
ella [17]

Step-by-step explanation:

Let the width be x feet.

Therefore, length = 2x - 10

Perimeter of rectangle = 52

2(2x - 10 + x) = 52 \\ 2(3x - 10) = 52 \\ \therefore \:  3x - 10 =  \frac{52}{2} \\ \therefore \:  3x - 10 = 26\\ \therefore \:  3x = 26 + 10\\ \therefore \:  3x = 36 \\ \therefore \:  x =  \frac{36}{3} \\ \therefore \:  x =  12 \\ \purple{ \boxed{\therefore \: width \: of \: rectangle = 12 \: feet }}

6 0
3 years ago
Find the domain of the function (f/g)(x) where f(x)=√x+1, g(x)=√x-9
nadya68 [22]

Answer:

4x + 9. Given f(x) = 2x + 3 and g(x) = –x2 + 5, find (g o g)(x). (g o g)(x) = g(g(x)) ... Given f (x) = sqrt(x) and g(x) = x – 2, find the domains of ( f o g)(x) and (g o f )(x). Since f (x) involves a square root, the inputs have to be non-negative. ... Given h(x) = (x + 1)2 + 2(x + 1) – 3, determine two functions f (x) and g(x

Step-by-step explanation:

4 0
3 years ago
An uncle wills 3000.00 to his 2 nieces and one nephew. The older niece is to receive twice what the younger niece receives and t
Semenov [28]

Answer:

Nephew receive 1500.00

Older niece receive 1000.00

Younger niece receive 500.00

Step-by-step explanation:

Let assume a variable x,y,z for the niece, older niece and the nephew respectively.

Y= 2x (Twice the younger niece)

Z= x + y. (Sum of the two nieces)

Since y = 2x

Z = x+2x

Z= 3x

Therefore:

X = 1x

Y = 2x

Z = 3x

So the will will be shared among them in the ratio

Nephew : older niece : younger niece

3 : 2 : 1

Nephew. 3/6 x 3000 = 1500.00

Older niece 2/6 x 3000 = 1000.00

Younger niece 1/6 x 3000 = 500.00

8 0
3 years ago
For 20 Points. 3 Qs.<br> I also gave you guys a help sheet. PLEASE HELP.
Eduardwww [97]
Wat is help sheet, didn't help,

instructions unclear, got my calculator stuck in the ceiling fan

remember some simple exponential laws
( x^{n} )(x^{m})=x^{n+m} and
\frac{x^{n}}{x^{m}} =x^{ n-m }
x^{-m}= \frac{1}{x^{m}}

first one
(2^{-6})(2^{3})=2^{-6+3}=2^{-3}= \frac{1}{2^{3}}  = \frac{1}{8}

2nd one
\frac{7^{5}}{7^{3}} =7^{ 5-3 } = 7^{2} = 49

third one
(3^{-4})(3^{2})=3^{-4+2}=3^{-2}= \frac{1}{3^{2}}  = \frac{1}{9}


dunno wat to do with 'help sheet'

4 0
3 years ago
A school day starts at 08:50 hrs. and ends at 15:00 hrs. There are two breaks. One lasting 20 minutes and the other 1 hour. How
Svetach [21]

Answer:

4:50 hrs to school activities

Step-by-step explanation:

the entire school day 6:10 hrs (with breaks)

so if we remove the breaks (which are 1:20hrs in total) we'll have 4:50hrs.

the equation would be: (the time the full day is)-(the total of breaks)= the school activity time.

so: 6:10hrs-1:20hrs= 4:50hrs

there's your answer. 4:50 hrs

*just remember i am working in the hrs format meaning 60 mins= 1hrs*

7 0
3 years ago
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